Find AC. Round to the nearest tenth. B 86° 16 С 11 A

Aubree practices the piano 1197 minutes in 3 weeks. At what rate did she practice, in minutes per day?

Norma-Jean [14]

Answer:

57

Step-by-step explanation:

We need to create a ratio. so Aubree practices the piano for 1197 min: in 3 weeks. So for 1 week, we have to divide 1197 by 3, so 1197/=399. And so we know that 1 week is 7 days, just divide 399 by 7! 399/7=57. The rate that she practiced per day is 57 minutes. So one last final step just to check if this answer is correct is to divide 57 by 60, and that is 0.95. 0.95 out of 1.00 minutes per day is 95/100. Cross multiply with x/60, and you will get your answer, which is 57.

4 0

2 years ago

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Zahra runs a 500-meter race at a constant speed. Which graph shows her distance from the finish line during the race?

makkiz [27]

Answer: The answer is the third figure. Attached the image.

Step-by-step explanation: Given that Zahra runs a 500-meter race at a constant speed. We are to select the correct graph from the four options that will show her distance from the finish line during the race.

We can see in graph 2, the distance covered by Zahra in metres increases at the same rate as the time increases in minutes.

But, since we are considering from the finish line, so option (#) will be right, because Zahra starts at 500 metres, decreases in the same manner as the increase of time and goes down to 0 on the positive X-axis.

Also,

Thus, the attached graph, which is the third option is the correct graph.

6 0

3 years ago

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In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe

enot [183]

Answer:

a)

$n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2$ , in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that $\pi = 0.16$

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which $M = 0.03$ . So