A. A Plus Plumbing company charges $60 per hour and $80 as a one-time fee cause 320-140/4-1 equals 180/3 equals 60 and y-140=60(x-1)
y=60x-60+140
y=60x+80
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Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
Answer:
53% or 0.53 or 53/100
Step-by-step explanation:
Answer:
108
Step-by-step explanation:
Given that Joseph has 48 comic books.
As he sold 1/4 of his collection to his friend, so
The number of books, Josef sold = 1/4 x 48 = 12.
The number of remaining books, Josef has = 48 - 12 = 36.
As he brought twice the number of comic books as he has now, so,
the number of comic books, Josef brought = 2 x 36 = 72.
Now, total number of comic books, Josef has = 36 + 72 = 108.