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EastWind [94]
3 years ago
10

A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 95% pure anti

freeze. In order to obtain 90 gallons of a mixture that contains 90% pure antifreeze, how many gallons of each brand of antifreeze must be used?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0
Let us represent the gallons of 65% antifreeze as x. If the total volume is 90 gallons, then the amount of 95% antifreeze can be written as (90 - x). Then we add up the total amount of antifreeze based on the volumes and percentages:
(0.65)x + (0.95)(90 - x) = (0.90)(90)
0.65x + 85.5 - 0.95x = 81
-0.3x = -4.5
x = 15
90 - x = 75
Therefore, 15 gallons of 65% antifreeze and 75 gallons of 95% antifreeze were used.
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Answer:

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Step-by-step explanation:

Primera etapa es de determinar cuantos tiros de Camilo acertaron al blanco.

Sabemos que en su última práctica, obtuvo 99 puntos con una mezcla de 5, 8 y 10 puntos.  Eso puedo se exprimir así:

5x + 8y + 10x = 99

Sabemos también que el obtuvo tantos tiros de 8 puntos que de 10 puntos, entonces

y = z

Podemos mezclar las 2 ecuaciones y substituir y por z:

5x + 8y + 10y = 99

5x +18y = 99

Una ecuación, dos variables... no es fácil... pero son números pequeños y se puede intentar soluciones.  Entonces, cuantas veces podemos multiplicar 5 y 18 para obtener 99?

El más simple es de hacer la tabla de multiplicación de 18 y ver cual número nos deja con un multiple de 5.

18 x 1 = 18 (99 - 18 = 81, no un multiple e 5)

18 x 2 = 36 (99 - 36 = 63, no un multiple de 5)

18 x 3 = 54 (99 - 54 = 45, SI, un multiple de 5)

18 x 4 = 72 (99 - 72 = 27, no un multiple de 5)

18 x 5 = 90 (99 - 90 = 9, no un multiple de 5)

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El tiró 9 veces por 5 puntos, 3 veces por 8 puntos y 3 veces pour 10 puntos.

En total tiró 15 veces.

Si acertó 75% (3/4) de las veces, cuantos tiros total?

\frac{15}{3/4} = \frac{15 * 4}{3} = 20

Camilo tiró 20 veces en total.

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