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EastWind [94]
3 years ago
10

A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 95% pure anti

freeze. In order to obtain 90 gallons of a mixture that contains 90% pure antifreeze, how many gallons of each brand of antifreeze must be used?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0
Let us represent the gallons of 65% antifreeze as x. If the total volume is 90 gallons, then the amount of 95% antifreeze can be written as (90 - x). Then we add up the total amount of antifreeze based on the volumes and percentages:
(0.65)x + (0.95)(90 - x) = (0.90)(90)
0.65x + 85.5 - 0.95x = 81
-0.3x = -4.5
x = 15
90 - x = 75
Therefore, 15 gallons of 65% antifreeze and 75 gallons of 95% antifreeze were used.
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since at (0,0) 0≤105(true), so area of 2x+3y≤105 will cover the origin.

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3 0
4 years ago
0.047×(9.2×10"4)<br><img src="https://tex.z-dn.net/?f=0.047%20%5Ctimes%20%289.2%20%20%5Ctimes%20%20%7B10%7D%5E%7B%3F4%7D%20" id=
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I don’t know if this is the correct answer because to the left of the four is there ? or “. I put it into the calculator as 10^4, so no ? or “.

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Answer:

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The answer is 26.

Step-by-step explanation:

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