The function has a maximum at (1, 3).
_____
You know it is not a minimum because the coefficient of the squared term is negative.
You know the vertex is (1, 3) because you match the pattern to
.. y = a(x -h)^2 +k
which has its vertex at (h, k).
Answer:
B= 
Step-by-step explanation:
If you noticed, A= 
BH is the formula for finding the area for a triangle. Your goal is to get B by it's self. Your first step will be to clear of the fraction first, so you will multiply both sides by 2. 2(A)=2(BH). On the left, you have 2×A= On the right side, you have 2(BH), but since you have a number in the equation, you will only use 2×. To solve 2×, you will cnacel out both 2's and you have 1. 1×BH will still equal BH, so you are now left will B×H.
(Your new equation looks like this by the way). 2A=BH
Since you need to get B by its self, the way to clear the H away from the B is by dividing. You will now divide the B and H aswell as 2A and H. (It will look like this) 
. (Again when you have the same number or letter, you cross it out. When you divide, you won't change anything on the left side, and all you have to do on the right id to cross out the H next to the B and cross out the H on the bottom of the equation). You should be left with = B. Now you can turn it around for your final answer. B= .
Please let me know if i helped, how I did, and if you have any questions.
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
The expression for the cost of Taxi B is 0.40<em>x</em> + 2.<em> </em>The expression for the cost of Taxi A is 0.20<em>x</em> + 4. The inequality asks for when the cost of Taxi B will be greater than Taxi A, so you write it as 0.40<em>x </em>+ 2 > 0.20<em>x</em> + 4, or 0.20<em>x</em> + 4 < 0.40<em>x </em>+ 2.
The answer is B) 0.20<em>x</em> + 4 < 0.40<em>x </em>+ 2.
