Answer:
Option B: a[k] = 20, a[k + 1] = 10 is the correct answer.
Explanation:
We will dry run the pseudocode line by line and monitor the values stored in elements to get the final answer.
We have three elements to be used in the code.
a[k] , a[k+1] and temp
a[k] = 10;
This line assigns value 10 to a[k]
a[k+1] = 20;
This line assigns value 20 to a[k+1]
temp = a[k];
This line will assign the value in a[k] to temp i.e. we have following values currently stored at the three locations a[k] = 10, a[k+1] = 20 and temp = 10
a[k] = a[k+1] ;
This line of code assigns the value of a[k+1] to a[k] which means now we have a[k] = 20 , a[k+1] = 20 and temp =10
a[k+1] = temp ;
This line will assign the value in temp to a[k+1] which means now we have
a[k] = 20 , a[k+1] = 10 and temp = 10
Hence, looking at the final values in a[k] and a[k+1] it can be concluded that
Option B: a[k] = 20, a[k + 1] = 10 is the correct answer
