Answer:
a.
Step-by-step explanation:
Since you have the different parabolas there, the simplest way to determine which one is, is replacing x as 0 and then y as 0
y = -1/4x^2 + 1
When x = 0
y = -1/4 (0)^2 +1 = 1
When y = 0
0 = -1/4x^2 +1
1/4 x^2 = 1
x^2 = 4
x = + 2
x = - 2
The parabola with points:
(0,1); (-2,0) and (2,0) is a.
400Let x = the number 10% of x = 400.10 x = 400.10x/0.10 = 40/0.10x = 400 check:10% of 400 = 400.10 * 400 = 4040=40
L x W = 105
L + W = 26 so L = 26 - W
substitute L = 26 - W into L x W = 105
(26 - W) x W = 105
26W - W^2 = 105
W^2 - 26W + 105 = 0
(W - 21)(W - 5) = 0
W - 21 = 0; W = 21
W - 5 = 0; W = 5
The the dimensions of the rectangle are 5 ft and 21 ft.
Double check:
The sum of the length and the width is 26 feet: 21 + 5 = 26 feet
A rectangle has an area of 105 square feet: 21 x 5 = 105 square feet
