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jekas [21]
3 years ago
5

Factor 15x + 35 using the GCF.

Mathematics
1 answer:
stellarik [79]3 years ago
4 0
The answer is A. 5(3x+7)
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The table below shows the cube roots of different numbers:
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part A)

\bf \begin{array}{|c|cccccc|ll} \cline{1-7} x&8&27&64&125&&x\\ \cline{1-7} y&\stackrel{\sqrt[3]{8}}{2}&\stackrel{\sqrt[3]{27}}{3}&\stackrel{\sqrt[3]{64}}{4}&\stackrel{\sqrt[3]{125}}{5}&&\sqrt[3]{x} \\ \cline{1-7} \end{array}~\hspace{10em}y = \sqrt[3]{x}

part B)

f(x) = 10 + 20x

so if you rent the bike for a few hours that is

1 hr.............................10 + 20(1)

2 hrs..........................10 + 20(2)

3 hrs..........................10 + 20(3)

so the cost is really some fixed 10 + 20 bucks per hour, usually the 10 bucks is for some paperwork fee, so you go to the bike shop, and they'd say, ok is 10 bucks to set up a membership and 20 bucks per hour for using it, thereabouts.

f(100) = 10 + 20(100) => f(100) = 2010.

f(100), the cost of renting the bike for 100 hours.

4 0
3 years ago
2(4x-3)>-3(3x)+5x help
Roman55 [17]

Answer:

x>1/2

Step-by-step explanation:

2(4x-3)>-3(3x)+5x

Expand the brackets.

8x-6>-9x+5x

Add -9x and 5x

8x-6>-4x

Add 4x and 6x on both sides.

8x+4x>6

Add the like terms.

12x>6

Divide 12 into both sides.

12x/12>6/12

x>1/2

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3 years ago
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A certain radioactive isotope has leaked into a small stream. Three hundred days after the​ leak, 3% of the original amount of t
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If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days
6 0
3 years ago
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