All categories

3 years ago

What ordered pairs are the solutions of the system of equations shown in the graph below?

Mathematics

1 answer:

WITCHER [35]3 years ago

8 0

Answer:

(-3,1) and (-8,6)

Step-by-step explanation:

Hey gabymcarrillo!

The solution is always the place where the two lines intersect.

Our first answer: go 3 left on the x- axis, and then go 1 up on the y- axis. This results in (-3,1)

Our second answer: go 8 left on the x- axis, then go 6 up on the y- axis. This results in (-8,6)

<em>Hope a helped, have a nice day!</em>

You might be interested in

Nishchal was listening to a song. Shown above are the views of his player showing 'Time elapsed' and 'Time remaining' for the so

mojhsa [17]

Answer: T = time remaining + time elapsed.

Step-by-step explanation:

Time elapsed means the time that he has been listening to the song (the minutes passed since he hits the play button)

Time remaining is the time left to finish the song.

Then the total duration of the song will be:

T = time remaining + time elapsed.

7 0

3 years ago

Find the unit rate. Enter your answer as a mixed number.

lesya [120]

The unit rate is the change of a quantity over one unit of another thus the unit rate of fertilizer covers is (30/8) foot per hour.

<h3>What is the rate of change?</h3>

The rate of change is the change of a quantity over 1 unit of another quantity.

Most of the time the rate of change is the change with respect to time.

For example the speed 3meter/second.

As per the given,

A fertilizer covers 5/8 square feet in 1/6 hour.

5/8 square feet ⇒ 1/6 hour

Multiply both sides by 6

6 × 5/8 square feet ⇒ 6/6 hour

30/8 square feet ⇒ 1 hour.

Hence "The unit rate is the change of a quantity over one unit of another thus the unit rate of fertilizer covers is (30/8) foot per hour".

To learn more about the rate of change here,

brainly.com/question/12786410

#SPJ1

5 0

1 year ago

Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern

Naya [18.7K]

Answer:

80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ( $\mu_1-\mu_2$ ) is [-9.132 , 23.332].

Step-by-step explanation:

We are given that a random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75.

A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25.

Firstly, the Pivotal quantity for 80% confidence interval for the difference between population means is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t__n__1-_n__2-2$

where, $\bar X_1$ = sample mean sales receipts for mail-order sales = $81.70

$\bar X_2$ = sample mean sales receipts for internet sales = $74.60

$s_1$ = sample standard deviation for mail-order sales = $18.75

$s_2$ = sample standard deviation for internet sales = $28.25

$n_1$ = size of sales receipts for mail-order sales = 7

$n_2$ = size of sales receipts for internet sales = 11

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(7-1)\times 18.75^{2} +(11-1)\times 28.25^{2} }{7+11-2} }$ = 25.11

<em>Here for constructing 80% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.</em>

<em />

So, 80% confidence interval for the difference between population means, ( $\mu_1-\mu_2$ ) is ;

P(-1.337 < $t_1_6$ < 1.337) = 0.80 {As the critical value of t at 16 degree

of freedom are -1.337 & 1.337 with P = 10%}

P(-1.337 < $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 1.337) = 0.80

P( $-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ${(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}$ < $1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.80

P( $(\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.80

<u>80% confidence interval for</u> ( $\mu_1-\mu_2$ ) =

[ $(\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ]

= [ $(81.70-74.60)-1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }$ , $(81.70-74.60)+1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }$ ]

= [-9.132 , 23.332]

Therefore, 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ( $\mu_1-\mu_2$ ) is [-9.132 , 23.332].

4 0

3 years ago

Jessica school bus stop is 60 yards from her house.For a normal school week, how many feet will Jessica walk to and from the bus

Lostsunrise [7]

Answer:

Step-by-step explanation:

school is only 5 days a week and if she walks 60 yards to the bus stop and 60 yards back from the bus stop than she walks a total of 120 yards a day

120 x 5 =600 the answers are in feet so we need to convert to feet and to do that we need to multiply by 3

600x3=1800

so she walks 1800 feet in a normal school week

6 0

3 years ago

Read 2 more answers

PLLLLLLLLLLLLLEASE PLEASE PLEASE PLEASE HELLLLLPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Vika [28.1K]

Answer:

The second one (B)

Step-by-step explanation:

u don't multiply a number by the same number if u know what I mean

hope this helps <3

5 0

3 years ago

Read 2 more answers