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2 years ago

What is the schumer box?

1 answer:

5 0

Description
The Schumer box is a summary of the costs of a credit card in the United States. It is named after Chuck Schumer, then New York congressman who was responsible for the legislation requiring that terms of credit cards be clearly outlined in any promotional material. Hope it helps

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Please explain your answer and I'll mark the Brainliest! Which complex number is the graph showing?

zheka24 [161]

Answer:

A 2√2(cos 7π/4 + i sin 7π/4)

Step-by-step explanation:

A. 2√2(cos 7π/4 + i sin 7π/4)

2 sqrt(2) ( sqrt(2)/2 - sqrt(2)/2 i)

Distribute

2-2i

This is in the fourth quadrant

B. 2√2(cos 150° + i sin 150°)

2 sqrt(2) (-sqrt(3)/2 +1/2i)

-sqrt(6) +sqrt(2) i

This is in the third quadrant (NO)

C. 2(cos 7π/4 + i sin 7π/4)

2( ( sqrt(2)/2 - sqrt(2)/2 i))

sqrt(2) - sqrt(2) i

This is the fourth quadrant

D. 2(cos 90° + i sin 90°)

2(0+i)

This is on the positive y axis NO

Now we need to decide between the two in the fourth quadrant.

The point has an x coordinate of 2 and a y coordinate of -2

This aligns with point A

8 0

3 years ago

Daisy has a pitcher that can hold 1000

mash [69]

Answer:

4.2

Step-by-step explanation:

Divide 1000 by 236 and you will get that result.

7 0

2 years ago

Graph the line with the given slope and y-intercept.<br> slope = 2. y-intercept =-5

Flura [38]

I'm attaching the graph of the above function

7 0

3 years ago

X^2-x-20 how do I write that in factored form

Rufina [12.5K]

Answer:

(x+4)(x-5)

Step-by-step explanation:

You need to find two numbers that multiply to be -20 but add up to be -1.

4 0

3 years ago

Read 2 more answers

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

3 years ago