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2 years ago

Which statement is true of z11.7?

Mathematics

1 answer:

Alexxx [7]2 years ago

7 0

Answer

z11.7 is between 1 and 2 standard deviations of the mean.

Step-by-step explanation:

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Find the mean, median, and mode of the data set. Round to the nearest tenth.

statuscvo [17]

The mean is the average of the data set. Median is the value that separates the higher half and the lower half of the set of values. Mode is the value that occurs often in the data set. Therefore, the correct answer is option A, <span>mean = 9.7, median = 10, mode = 15</span>

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3 years ago

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Distributive property for x(11+2), please????

Hitman42 [59]

Answer: 13x

Step-by-step explanation: Multiply x to 11 and 2

11x+2x=13x

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1 year ago

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How do I solve for x?

zheka24 [161]

3.) 5x-6=0, Add 6 to either side -> 5x=6, divide each side by 5 -> x=6/5 ---- 4.) x+y/3=5, multiple each side by 3 -> x+y=15, move y to the other side -> x=-y+15

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3 years ago

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Is the following expression true or false? [x^2 + 8x + 16] · [x^2 – 8x + 16] = (x2 – 16)^2

Vilka [71]

$(x^{2} +8x+16)(x^{2} -8x+16)\\(x+4)^{2} (x-4)^{2} \\(x^{2}-16)^{2} \\$

it is true; just work them out, you should get what they got :))

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3 years ago

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In a research laboratory, a scientist measures the mass of a 1-carat diamond and finds it to be 200 milligrams, measured to the

vlada-n [284]

Answer:

$D=3.5\ gr/cm^3$

Step-by-step explanation:

<u>Density</u>

The density of an object of mass m and volume V is given by

$\displaystyle D=\frac{m}{V}$

It can be expressed in common units like $gr/lt, Kg/m^3, gr/cm^3$ or any other combination of proper mass [M] by volume [V] units.

The data provided in the question is

$m=200\ mg = 0.2\ gr$

$V=0.057\ cm^3$

Thus, the measured density is

$\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}$

$\boxed{D=3.5\ gr/cm^3}$

We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.

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3 years ago