Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Answer:
y=-5x-12
y=-0.5x-5
y=-0.5x+0.5
y=-4.5x+3
y=-2x+7
y=2.5x+10
Step-by-step explanation:
The believe the answer is m=9.
4 + 3x = 12
3x = 12 - 4
3x = 8
x = 8/3
x = 2,6 grams
Answer:
47 cards remain
Step-by-step explanation:
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