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3 years ago

A parallelogram has a base of 7.7 millimeters and a height of 8 millimeters. What is the area?

Mathematics

2 answers:

ololo11 [35]3 years ago

8 0

61.6 millimeters is the area

Strike441 [17]3 years ago

6 0

A= b.h
A= (7.7 mm)(8mm)
A= 61.6 mm2

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3 years ago

the frame of a picture is 28 cm by 32 cm outside and is of uniform width.What is the width of the frame if 192 cm2 of the pictur

natita [175]

Answer:

The width of the frame is equal to $8\ cm$

Step-by-step explanation:

Let

x-------> the width of the frame picture

we know that

$(28-2x)(32-2x)=192$

$896-56x-64x+4x^{2} =192$

$4x^{2}-120x+704=0$

Simplify

$x^{2}-30x+176=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-30x+176=0$

$a=1\\b=-30\\c=176$

substitute in the formula

$x=\frac{30(+/-)\sqrt{(-30)^{2}-4(1)(176)}} {2(1)}$

$x=\frac{30(+/-)\sqrt{196}} {2}$

$x=\frac{30(+/-)14} {2}$

$x=\frac{30+14} {2}=22\ cm$ ----> this solution is not logic

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3 years ago

Terrance claims that for the input coordinates (x, y), a rotation of 180° clockwise about the origin, followed by a reflection o

vodka [1.7K]

Answer:

Terrance is incorect.

Correct output coordinates (-y,-x)

Step-by-step explanation:

Let $(x,y)$ be the input coordinates.

First translation is a rotation of 180° clockwise about the origin. This translation has a rule

$(x,y)\rightarrow (-x,-y)$

Second translation is a reflection over the line y = x. The general rule for the reflection across the line y=x has the rule

$(a,b)\rightarrow (b,a)$

When a sequence of two translations are applied to the initial input coordinates, then

$(x,y)\rightarrow (-x,-y)\rightarrow (-y,-x)$

As you can see Terrance made a mistake and these two transformations do not cancel themselves out.

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2 years ago

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Answer:

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