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earnstyle [38]
3 years ago
5

What is the slope of the line that passes through the points shown in the table?

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

Where is the table???

Step-by-step explanation:

Show the full question

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PLZ HELP!!!<br> what r the answers??
vekshin1

Answer:

Question 2 the answer is C) y = -3/2x + 2

Question 3 the answer is D) x = 4

Step-by-step explanation:

To solve either we first need to know that parallel lines have the same slope.

So in #2 we know that the new line will also have a slope of -3/2. Therefore, we can use that along with the point given in the problem in point-slope form to get the new equation.

y - y1 = m(x - x1)

y + 1 = -3/2(x - 2)

y + 1 = -3/2x + 3

y = -3/2x + 2

And for #3, we know that we have a vertical line due to the fact that it is expressed as x = a number. Therefore, we must have the same in the answer. D is the only one that has such an answer.

3 0
3 years ago
Which statement explains Joni’s error?
USPshnik [31]

Answer:

um can i see the statements?

Step-by-step explanation:


8 0
3 years ago
The cosine ratio is used to find missing angle measures and side measures in
VashaNatasha [74]
... right triangles.
7 0
3 years ago
What are the solutions to the quadratic equation x^2-16=0
frutty [35]
Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4
8 0
3 years ago
Read 2 more answers
9. Calcule el valor de la fuerza que experimenta un ascensor cuando levanta 150 kg en los siguientes casos: a) Cuando asciende c
GenaCL600 [577]

Answer:

a) La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) Por la fuerza de tensión sobre el cable del ascensor.

Step-by-step explanation:

a) La fuerza neta experimentada por el ascensor (F), en newtons, es:

F = m\cdot a (1)

Donde:

m - Masa, en kilogramos.

a - Aceleración, en metros por segundo cuadrado.

Si sabemos que m = 150\,kg y a = 4\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = 600\,N

La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) Si sabemos que m = 150\,kg y a = -6\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = -900\,N

La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) De manera simplificada, el ascensor experimenta dos fuerzas que definen la fuerza y aceleración netas: (i) La fuerza de tensión sobre el cable que traslada el ascensor y el peso total del ascensor, opuesta a la anterior y en función de la aceleración gravitacional. Puesto que la masa no varía en ningún caso, se concluye que el peso es constante, entonces la diferencia de valores se debe a la fuerza por tensión del cable. En el descenso, es fuerza es menor que en el ascenso.

8 0
3 years ago
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