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3 years ago

Help me with this plzzzz

Mathematics

1 answer:

Alex17521 [72]3 years ago

8 0

Answer:

I believe the answer is B 67%

Step-by-step explanation:

you would divide 246 by 365 to get 0.6739... and if you multiply by 100 that would be your answer of 67%

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N the sequence generated by the formula an = n – 4, which term has a value of 8?

Mrrafil [7]

Answer:

The twelfth term :)

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6 0

3 years ago

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A chess club with 55 members is electing a new president. Lucy received 33 votes. What percentage of the club members voted for

bonufazy [111]

You would put it up into proportions so 33 over 55 equals x over 100. Then you would cross multiply so 55x=3300. Then you would divide 3300 by 55 and get 60%.

4 0

3 years ago

Sammy opened a college savings account. She opened the account with $85, and then

MrMuchimi

Answer:

C. s= 85m + 45

Step-by-step explanation:

Given data

She opened the account with $85

and deposited $85

The equation that best models the relationship is

s= 85m + 45

Hence option C is correct

8 0

2 years ago

Slope is –2 & (5, 3) is on the line.<br> Y-Intercept:<br> Equation of the line (no spaces):

GREYUIT [131]

Answer:

The y intercept is (0,13)

The equation of the line is y = -2x+13

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = -2x+b

Substituting the point

3 = -2(5) +b

3 = -10 +b

Add 10 to each side

13 =b

The y intercept is (0,13)

The equation of the line is y = -2x+13

5 0

3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

#SPJ9

6 0

1 year ago

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Help me with this plzzzz​

Help me with this plzzzz