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3 years ago

6+5 x 2 +5+ = 67 +84 - 12 x 4 = 16

Mathematics

1 answer:

lozanna [386]3 years ago

3 0

Answer:

6+(5 x 2)+5=21

the way you wrote this was kinda weird so I don't know what you expected as an answer

Step-by-step explanation:

5 x 2=10

10+6=16

16+5=21

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Consider the following function. f ( x ) = 1 − x 2 / 3 Find f ( − 1 ) and f ( 1 ) . f ( − 1 ) = f ( 1 ) = Find all values c in (

Ksenya-84 [330]

Answer:

(E)Nothing can be concluded.

Step-by-step explanation:

Given the function $f(x)=1-x^{\frac{2}{3}}$

$f(-1)=1-(-1)^{\frac{2}{3}}=1.5-0.86603i\\f(1)=1-1^{\frac{2}{3}}=1-1=0$

$f'(x)=-\dfrac{2}{3}x^{-\frac{1}{3}}\\f'(x)=-\dfrac{2}{3\sqrt[3]{x} }$

If the derivative is set equal to zero, the function is undefined.

Nothing can be concluded since $f(1)\neq f(-1)$ and no such c in (-1,1) exists such that $f'(c)=0$

THEOREM

Rolle's theorem states that any real-valued differentiable function that attains equal values at two distinct points must have at least one stationary point somewhere between them—that is, a point where the first derivative is zero.

4 0

4 years ago

kelly ate 5/8of a pizza,lilly ate 2/6 of a pizza,ray ate 8/11 of a pizza,and marlin ate 2/5 of a pizza.which girl ate the least

kap26 [50]

5/8, 2/6, 8/11, 2/5
Convert them into decimals.

5/8 ⇒ 0.625
2/6 ⇒ 0.333
8/11 ⇒ 0.727
2/5 ⇒ 0.4

The lowest amount is 0.333, or 2/6.

Lilly ate 2/6 of a pizza.
Lilly ate the least amount of pizza.

7 0

3 years ago

Need help :( . . . . I need to pass it tomorrow..

koban [17]

Answer:

across

3. 6x

4. 14mn

5. 31

6. 25b

9. 5abc

down

1. 3y

4. 19m

5. 3m2np2

7. 7y

8. 9x

Step-by-step explanation:

hope this helps

4 0

2 years ago

The diameters of Douglas firs grown at a Christmas Tree Farm are normally distributed with a mean of 4 inches and a standard dev

leva [86]

Answer:

The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.

Step-by-step explanation:

In this problem we have a normal ditribution with mean of 4.0 in and standard deviation of 1.5 in.

The proportion of the trees that are expected to have diameters greater than 5 inches is equal to the probability of having a tree greater than 5 inches.

We can calculate the z value for x=5 in and then look up in a standard normal distribution table the probability of z.

$z=\frac{x-\mu}{\sigma}=\frac{5-4}{1.5}=0.67$