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Answer:
The baseball would seem to be traveling with a velocity 0.98918c of 98.92% of the speed of light as seen from the Earth.
Explanation:
This problem involves the relativistic effects. The pitcher throws the ball with a velocity u' which is 65% of the speed of light c i.e. u' = 0.65c
The velocity V of the spaceship in which he is practicing is 95% of the speed of light. Therefore V = 0.95c
So if the ball is thrown in the same direction as the direction of the spacecraft's motion, then classically, the velocities would add up and exceed the speed of light. But we know that this is not possible. It is prohibited by the special theory of relativity. So we need to consider the relativistic addition of velocities to calculate the velocity (u) of the ball as seen from the Earth.
The formula for relativistic addition of velocities is expressed below,
We know that u' = 0.65c and V = 0.95c. now we can calculate u which is the velocity of the baseball as seen from Earth as follows
u = 0.98918c
So the baseball would seem to be traveling with a velocity 0.98918c of 98.92% of the speed of light as seen from the Earth.