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Naddika [18.5K]
3 years ago
13

I am in need of assistance.

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

A. x = 6.08, x = -0.58

Step-by-step explanation:

  • \displaystyle \frac{2x}{x-4}-\frac{2x-5}{x^2-10x+24}=\frac{-3}{x-6}

1. Factor the denominator.

  • \displaystyle \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}

2. Multiply the leftmost fraction by (x-6)/(x-6) to get common denominators.

  • \displaystyle \Big ( \frac{x-6}{x-6} \Big ) \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}

3. Simplify.

  • \displaystyle \frac{2x^2-12x}{(x-4)(x-6)}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}  

4. Combine like terms.

  • \displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6}  

5. Multiply the right side of the equation by (x-4)/(x-4).

  • \displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6} \Big ( \frac{x-4}{x-4}  \Big )  

6. Simplify.

  • \displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3x+12}{(x-6)(x-4)}

7. "Cancel" out the denominators because they are equivalent.

  • 2x^2-14x+5=-3x+12

8. Set the equation equal to 0.

  • 2x^2-11x-7=0

Quadratic formula:

  • \displaystyle x = \frac{-b\pm \sqrt{b^2-4ac} }{2a}  

9. Factor using the quadratic formula.

  • \displaystyle x = \frac{-(-11)\pm \sqrt{(-11)^2-4(2)(-7)} }{2(2)}

10. Multiply and simplify.

  • \displaystyle x = \frac{11 \pm \sqrt{177} }{4}

11. Plug this into your calculator and solve for x.

  • x=6.07603367 \approx 6.08
  • x=-0.57603367 \approx -0.58

The correct answer is A. x = 6.08, x = -0.58.

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