Answer:
B. {1, 2, 2, 3, 3, 4, 5}
Explanation:
Given
The above code segment
Required
Determine which list does not work
The list that didn't work is 
Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3
All other list do not have consecutive duplicate numbers
Option B can be represented as:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 2](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%202)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 3](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%203)
![nums[5] = 4](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%204)
![nums[6] = 5](https://tex.z-dn.net/?f=nums%5B6%5D%20%3D%205)
if (nums.get(j).equals(nums.get(j + 1)))
The above if condition checks for duplicate numbers.
In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 3](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%203)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 4](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%204)
![nums[5] = 5](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%205)
The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.
<em>This is so because of the way the if statement is constructed.</em>
Answer:
<u>algorithm</u>
original = float(raw_input("Enter initial balance: "))
interest = float(raw_input("Enter promised return: "))
expenses = float(raw_input("Enter monthly expenses: "))
interest = interest / 100 / 12
month = 0
balance = original
if balance * interest - expenses >= 0:
print "You don't need to worry."
else:
while balance + balance * interest - expenses >= 0: # negation of the if condition
balance = balance + interest * balance # in one month
balance = balance - expenses
month = month + 1
print month, balance
print month / 12, "years and", month % 12, "months"
I think that would be the stages of deletion bro.
Hope it helps
ASCII is an agreement on which number represents which typographic character. Using this table you can look up the number of any character. For instance, "A" has 65, but that is a decimal. Next step is to represent this decimal number in hexadecimal. You can do that by taking the divisor and remainder of a division by 16. Numbers beyond 9 are represented as a through f. Hexadecimal numbers are commonly prefixed by "0x" to make them recognizable.
So "A" = 65 = 4*16+1 = 0x41
And "Z" = 90 = 5*16+10 = 0x5a
There are ASCII tables that have the hexadecimal value in them, to make the task easier (www.asciitable.com).
If you want to do this programmatically, you can write something like this (node.js):
console.log( Buffer.from('AZ', 'utf8').toString('hex'));
Note that the 0x prefix is not shown here.