Answer:
1436.02
Step-by-step explanation:
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
A. -100
Step-by-step explanation:
1.) To single out x, follow the opposite operation on both sides. Firstly, we begin with:
X/5 + 6 = -14
Then the opposite operation from addition is subtraction, therefore:
X/5 + 6 - 6 = -14 - 6,
X/5 = -20
Then the opposite operation from division is multiplication, therefore:
X/5 x 5 = -20 x 5
X = -100
Answer:
B
Step-by-step explanation:
