All categories

3 years ago

A leaking faucet drips into a bucket. The faucet drips at a constant rate. The level of water in the bucket rises

Mathematics

1 answer:

Sveta_85 [38]3 years ago

7 0

Answer:

The per hour rate is 0.5 inches per hour

Step-by-step explanation:

Here, we want to calculate the rate at which the level of the water increased

Mathematically, we can get this by dividing the amount of increment by the time it took

That would be 3 inches divided by 6 hours

= 3/6 = 0.5 inches per hour

You might be interested in

What are all real square roots of .027

mario62 [17]

Answer:

Step-by-step explanation:

The principal, real, root of:

$^{2} \sqrt{0.027}$

= 0.164316767

All roots:

0.164316767

−0.164316767

0.027 is not a perfect square

5 0

3 years ago

HURRYYYY

kati45 [8]

63 study French
30 French not Spanish
63 study Spanish

3 0

4 years ago

Read 2 more answers

Given that (-5,-6) is on the graph of f(x), find the corresponding point for this function -1/3f(x).

masya89 [10]

<h3>Answer: (-5, 2)</h3>

Explanation:

We multiply the y coordinate by -1/3 because of the notation (-1/3)*f(x). Recall that y = f(x). The x coordinate stays the same.

5 0

2 years ago

Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3

LekaFEV [45]

Answer:

$(a)\ \sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128} = 8 \sqrt{2}$

Step-by-step explanation:

Required

Simplify

$(a)\ \sqrt{20}$

Express 20 as 4 * 5

$\sqrt{20}=\sqrt{4 * 5}$

Split

$\sqrt{20}=\sqrt{4} * \sqrt{5}$

This gives:

$\sqrt{20}=2 * \sqrt{5}$

$\sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300$

Express as 100 * 3

$\sqrt{300} = \sqrt{100} * \sqrt{3}$

This gives:

$\sqrt{300} = 10 * \sqrt{3}$

$\sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128}$

Express as 64 * 2

$\sqrt{128} = \sqrt{64*2}$

Split

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0

3 years ago

Judy is pulling on a trunk with a 12-N force. Ike pulls at right angles to Judy. With how much force must Ike pull to make the r

Ratling [72]

To understand the problem, let's first draw a free body diagram of the forces exerted by Judy and Ike on the truck. (Refer to the left side of the attachment).

To solve for the resultant, we just use the tip-to-tail method. This is illustrated on the right side of the attachment.

We can see that the tip-to-tail method forms a right triangle thus we can just apply the Pythagorean theorem in solving for Ike's force.

$20^{2} = 12^{2} + F^{2}$
$400 = 144 + F^{2}$
$256 = F^{2}$
$F = 16.0$

ANSWER: Ike must pull the truck with a force of 16.0 N.

8 0

3 years ago