To get a close estimate, we can round 49 up to 50 and 311 down to 300, obtaining an estimate of 50/300 = 1/6, or 0.1666... as a repeating decimal. That decimal approximation is a little less than one hundredth away from the actual decimal approximation of ≈ 0.1576
The distance covered by a free-falling object in 'T' seconds after it's dropped is
D = (1/2) x (gravity acceleration) x (T²)
Gravity acceleration on Earth is 9.8 m/s². or 32.2 feet/sec² .
20-ft = (1/2) (16.1) (T²)
20 = 8.05 T²
T = √(20/8.05) = <u>1.576 seconds .</u>
Answer:
2/3
Step-by-step explanation:
Calculators help :)