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3 years ago

Which expressions are equivalent to this exponential expression?

Mathematics

1 answer:

gregori [183]3 years ago

8 0

Remember that when the exponents look like this (5^2)^-3, you multiply the exponents together

when it looks like this:
5^3 x 5^2 you add the exponents
so my example would equal 5^5

also remember that you can’t have negative exponents

To solve your problem:
1. multiply the exponents here: (5^2)^-3

2. add the exponents in the next step when you multiply by the 5^4

3. now, you should get a negative exponent on the top, and you already have one on the bottom. to get rid of these negative exponents, move the one in the denominator to the numerator and vice versa

so when you move the 5^-4 in the denominator to the numerator, it becomes 5^4

4. now, you simplify. you can either subtract the exponents and do it that way, or you can solve the exponents and then divide. either way will work, although the first is easier

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Which system can be used to represent, x the number of tetra fish, and y, the number of goldfish, he purchased?

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The equation that would best describe the situation would be the first option. To solve this question, simply break down the question into sections and then use variables X and y to represent each of the things asked for in the problem. We know the following:

X = no of tetra fish
Y = no of goldfish
If there is twice as much goldfish than tetra fish, then it would be 2y.

X = 2Y.

Then knowing what X and y represent, find the equation that gives the total cost of fish he bought, knowing that 1.50 is for a goldfish and 2.00 is for a tetra fish.

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3 years ago

Tracy found the length of GF. Her work is shown below.

Sveta_85 [38]

she used GF=2BG,but the statement is correct BG=2GF

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3 years ago

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Assume that when adults with smartphones are randomly selected, 46% use them in meetings or classes. If 9 adult smartphone use

valina [46]

Answer:

0.18173219.

Step-by-step explanation:

We have been asked to find what will be the probability that at least 6 of 9 adults use their smartphones in meetings or classes.

We will find our answer using Bernoulli's trails.

$_{r}^{n}\textrm{c}\cdot p^{r}\cdot (1-p)^{n-r}$

First of all we will find the probabilities when r is 6, 7,8 and 9 then we will add them all.

When r=6,

$_{6}^{9}\textrm{c}\cdot 0.46^{6}\cdot (1-0.46)^{9-6}$

$\frac{9!}{6!3!} *0.46^{6} *0.54^{3}$

$\frac{9*8*7*6!}{6!*3*2*1} *0.009474296896*0.157464$

$84*0.009474296896*0.157464=0.12532$

Similarly we will find Probabilities when r=7, 8 and 9.

When r=7

$_{7}^{9}\textrm{c}\cdot 0.46^{7}\cdot (1-0.46)^{9-7}$

$\frac{9!}{7!2!} *0.46^{7} *0.54^{2}$

$\frac{9*8*7!}{7!*2*1} *0.00435817657216*0.2916$

$36*0.00435817657216*0.2916=0.04575039$

When r=8

$_{8}^{9}\textrm{c}\cdot 0.46^{8}\cdot (1-0.46)^{9-8}$

$\frac{9!}{8!1!} *0.46^{8} *0.54$

$\frac{9*8!}{8!*1!} *0.00200476*0.54$

$9 *0.00200476*0.54=0.0097431336$

When r=9,

$_{9}^{9}\textrm{c}\cdot 0.46^{9}\cdot (1-0.46)^{9-9}$

$\frac{9!}{9!0!} *0.46^{9} *1$

$1 *0.00092219*1=0.00092219$

Now let us add all the probabilities to get the final answer.

$0.12532+0.04575+0.00974+0.00092219=0.18173219$

Therefore, probability that at least 6 of 9 adults use their smartphones in meetings or classes is 0.18173219.

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4 years ago

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Please help I don’t understand it

slavikrds [6]

The constant is 3.

This is because when x=1, y=3 and when x=2, y=6 so that is a constant change over each interval as seen in the graph which is 3 :)

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3 years ago

mai is running for president of the chess club and she received 36 votes there are 40 members in the club what percentage of the

Drupady [299]

Answer:

Step-by-step explanation:

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