Given the function f, match the function g with a transformation of f.

f(x) = x2 + 1, g(x) = (x - 2)2 + 1

☆☆☆☆☆☆☆☆a) f(x + 2)

b) f(x) + 2

c) f(x) - 2

d) f(x - 2)

The transformation that occured was a horizontal shift to the right of all the x's.

3 0

3 years ago

X/3 - ( -2) =16 and its 7 th grade algebra btw i need help

Novosadov [1.4K]

Answer x/3 -(-2)= 16

X/3+ 2=16

X/3=16-2

X/3=14

X= 14x3=42

Step-by-step explanation:

3 0

3 years ago

1. |4n-15|=|n|<br> 2. |2c+8|=|10c| <br> can you please show the work for both

Alja [10]

Problem 1

<h3>Answers: n = 3 or n = 5</h3>

---------------

Work Shown:

$|4n - 15| = |n|\\\\4n - 15 = n \ \text{ or } \ 4n-15 = -n\\\\-15 = n-4n \ \text{ or } \ -15 = -n-4n\\\\-15 = -3n \ \text{ or } \ -15 = -5n\\\\-3n = -15 \ \text{ or } \ -5n = -15\\\\n = \frac{-15}{-3} \ \text{ or } \ n = \frac{-15}{-5}\\\\n = 5 \ \text{ or } \ n = 3\\\\$

==============================================

Problem 2

<h3>Answers: c = 1 or c = -2/3</h3>

-----------------------

Work Shown:

$|2c+8| = |10c|\\\\2c+8 = 10c \ \text{ or } \ 2c+8 = -10c\\\\8 = 10c-2c \ \text{ or } \ 8 = -10c-2c\\\\8 = 8c \ \text{ or } \ 8 = -12c\\\\8c = 8 \ \text{ or } \ -12c = 8\\\\c = \frac{8}{8} \ \text{ or } \ c = \frac{8}{-12}\\\\c = 1 \ \text{ or } \ c = -\frac{2}{3}$

8 0

3 years ago