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nignag [31]
4 years ago
7

Write a java program that determines the position of the hour and minute hands of an analog clock at a moment in time. using a 1

2-hour clock (where the hour hand moves between the integers 1 thru 12 and the minute hand moves between the integers 0 and 59), read the current clock time from the user and then read a time increment to add to or subtract from the current time. for this second time, calculate where the location of the hour and minute hand will be.
Mathematics
1 answer:
Keith_Richards [23]4 years ago
4 0
<span>Using a 12-hour clock (where the hour hand moves between the integers 1 thru 12 and the minute hand moves between the integers 0 and 59), read the current clock time from the user and then read a time increment to add to or subtract from the current time.</span>
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2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
Oksana_A [137]

Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
4 years ago
A prism and two nets are shown below:
nikdorinn [45]
Part a : Net A because when you fold it up it will look like the wanted prism

Part b : AB = 3 in
BC = 5 in
CD = 7.2 in

Part c : area of one triangle = 4*3 = 12 / 2 = 6
6 * 2 = 12 (because there are 2 triangles)
7.2 * 3 = 21.6
7.2 * 4 = 28.8
7.2 * 5 = 36
Add them all up : 12+21.6+28.8+36 = 98.4
So surface area is 98.4 in
4 0
3 years ago
Solve 5.6-13/8-3.9+2 3/4
AlekseyPX

Answer:

65

Step-by-step explanation:

3 0
3 years ago
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5th GRADE MATH! Select the statement that correctly compares two numbers. A. 6,092 &gt; 6,092.001 B. 6,197.02 &gt; 6,197.2 .C 6,
Lilit [14]

Answer:

D is correct

Step-by-step explanation:

A is incorrect because the lesser than is .001 higher

B is wrong since is .18 higher

C is wrong because its not equalone is .9 higher

7 0
3 years ago
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kaitlin buys 9/10 pound of orange slices. she eats 1/3 of them and divides the rest equaly into 3 bags. how much is in each bag
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2/10

1/3 of 9/10 would be 3/10

this leaves you with 6/10

divided into 3 bags leaves you with 2/10 in each bag
6 0
3 years ago
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