Answer:
P(x) = (x-1)² (x-3)
Step-by-step explanation:
P(x)=x³- 5x² + 7x-3 = x² (x-1) - 4x(x-1) + 3(x-1) = (x²-4x+3)(x-1)
P(x) = (x-1)(x-3)(x-1) = (x-1)² (x-3)
We need to know this:
If Δ > 0 we have two and different solutions
If Δ = 0 we just one solution
If Δ < 0 we don't have real solutions
Answer:
-1.44285714286
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Using the cofunction identities
tan(90 - A) = cotA and cscA = sec(90- A)
Consider the left side
tanA + tan(90 - A)
= tanA + cotA
=
+ 
= 
= 
=
× 
= secA × cscA
= secA. sec(90 - A) = right side ⇒ verified
Answer:
can yall look at my post
Step-by-step explanation: