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uranmaximum [27]

3 years ago

8

The drawings above represent the tablecloths Margot is thinking about buying. She plans to sew a decorative fringe on the tablec

loth. About how much fringe will Margot have to sew on the round tablecloth?

2 answers:

Mariana [72]3 years ago

5 0

Answer:

I'm assuming you're talking about the question in the picture:

If so, the answer

D. 12

Rina8888 [55]3 years ago

4 0

Bestie you didnt add the photo

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If your annual pay is $36,010, what is your biweekly pay based on 26 biweekly paychecks?

Anuta_ua [19.1K]

To get your bi weekly pay you would divide $36,010 by 26, seeing as bi weekly means you get payed every other week.
36,010 / 26 = $1,385
I hope this helps :)

4 0

4 years ago

Factor completely<br> 374 +48r2

irakobra [83]

Answer:

2(187 + 241r)

Step-by-step explanation:

3 0

3 years ago

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago

Please help me in this question

Arisa [49]

Find lcm of 28 and 36 which is 252. They will meet again in another 252 days.

5 0

3 years ago

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Will give brainliest if correct!

Nata [24]

Answer:

option c. figure b.......

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3 years ago

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