Im pretty sure the answer is a
Answer:
The probability that the mean of a sample of 36 cars would be less than 3245 miles
P(X⁻≤3245) = 0.975
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
The mean number of miles between services
μ= 3408 miles
The Variance of miles between services
σ² = 249,001
σ = √249,001 = 499
Let 'X' be a random variable in a normal distribution
Given sample size 'n' =36
<u><em>Step(ii):</em></u>-
Z = -163/83.16 = 1.96
The probability that the mean of a sample of 36 cars would be less than 3245 miles
P(X⁻≤3245) = P(Z≤1.96)
= 0.5 + A(1.96)
= 0.5 + 0.4750
= 0.975
<u><em>Final answer</em></u>:-
The probability that the mean of a sample of 36 cars would be less than 3245 miles
P(X⁻≤3245) =0.975
For the carpet:
Given:
Area = x^2 + x - 20 ft^2
Length = x+ 5 ft
As a carpet is rectangular, the area is defined as the product of the length and the width. To obtain an expression of the carpet's width, the area is to be divided by the length, which is shown below:
__x_-_4___x + 5|x^2 + x - 20 x^2 + 5x -------- -4x - 20 -4x - 20 -------- 0
Therefore, the expression of width = x - 4.
Applying the value of x = 20 to obtain the measurements of the carpet, we obtain the following:
Width = x - 4 = 20 - 4 = 16ft
Length = x+ 5 = 20 + 5 = 25ft.
Therefore, the carpet is 25ft x 16ft.
For the wall:
The same principles apply to the wall as it is also assumed to be rectangular.
Given:
Area = <span>x^2 + 17x + 30 ft^2
Width = x + 2
To obtain the expression for the wall's length, Area is to be divided by the Width, which is shown below:
__x_+_15______x + 2|x^2 + 17x + 30 x^2 + 2x -------- 15x + 30 15x + 30 --------- 0
Therefore, the expression for the wall's length is x + 15.
Applying the value of x = 20 to obtain the wall's dimensions:
Length = x + 15 = 20 + 15 = 35ft.
Width = x + 2 = 20 + 2 = 22ft.
Therefore the wall has measurements of 35ft x 22ft.</span>
Answer:
AA similarities
Step-by-step explanation:
FG //KJ
FHG=JHK
others by alternate angles
Answer:
Step-by-step explanation:
9-3z+4+6z-2
13-2+3z
11+3z
