1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonbull [250]
3 years ago
15

Sue owes an amount of £800

Mathematics
1 answer:
LekaFEV [45]3 years ago
8 0

Answer:

She will have £262 left to pay at the end of five months.

Step-by-step explanation:

Exponential equation for an amount:

A exponential equation for an amount that decays has the following format:

A(t) = A(0)(1-r)^{t}

In which A(0) is the initial amount, r is the decay rate, as a decimal, and t is the time measure.

Sue owes an amount of £800

This means that A(0) = 800

Each month, she pays back 20% of the amount she still owes.

This means that r = 0.2

So

A(t) = A(0)(1-r)^{t}

A(t) = 800(1-0.2)^{t}

A(t) = 800(0.8)^{t}

How much will she still have left to pay at the end of five months?

This is A(5). So

A(5) = 800(0.8)^{5} = 262

She will have £262 left to pay at the end of five months.

You might be interested in
How do you do this??
ruslelena [56]

Answer:

bxc+ax32=0

Step-by-step explanation:

7 0
3 years ago
What is the proportion of 22/3
Rudiy27

Answer:

not to sure but is it  733.333333333333%

Step-by-step explanation:

4 0
3 years ago
IAN LEAVES NORFOLK VA TRAVELING WEST AT 50MPH ANDREW LEAVES NORFOLK VA 3 HOURS LATER TRAVELS IN THE SAME DIRECTION GOING 68 MPH.
Paladinen [302]
Approximately 5 hours

4 0
4 years ago
Please help me . Find x.
Paladinen [302]

Answer:

12) 5.96 ; 13)

Step-by-step explanation:

12). x and 5 are legs, so

opposite leg/adjacent leg = tangent 40°

5/x= tan40°,    5= x*tan40°, x= 5/tan40° ≈ 5.96

13). 15 is opposite leg

24 is hypotenuse

opposite leg/hypotenuse = sin(x)

sin(x) = 15/24

x = arcsin(15/24) ≈ 38.68°

6 0
3 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
4 years ago
Other questions:
  • HEEEEEEEEEEEEELLLLLLLLLLLLLP!!!!!! PLZZZZZZZZ
    11·1 answer
  • A staircase handrail is made from congruent parallelograms. in parallelogrampqrs, pq = 17.5, st = 18, and m∠ qrs = 110° . find m
    15·1 answer
  • Which of the following expressions would appear farthest to the right on a number line when solved?
    8·2 answers
  • What is 90.69 rounded to the nearest tenth
    6·2 answers
  • 12 lb13 oz + 6 lb11 oz
    6·1 answer
  • Trish has two containers of water for a camping trip. One container holds 2 times as much as the other. The total amount of wate
    5·1 answer
  • Find the volume of the right circular cone that’s has the radius of 4 inches and height of 12 inches
    12·1 answer
  • What is the height of a triangle with<br>base 7cm and area of 35cm 2<br>​
    10·1 answer
  • How to solve a system of two linear equations:
    13·1 answer
  • The variables x and y have a proportional relationship, and y=5/6 when x=3/4. Which equation represents this relationship?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!