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sashaice [31]
3 years ago
6

Which of the following conversions is possible?

Mathematics
1 answer:
Mkey [24]3 years ago
4 0

Answer:

Feet to Miles

Step-by-step explanation:

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What 2 numbers add to -3 and multiply to 2
serg [7]
We need to look at factors of 2, which are only 2 and 1... How do we get them to add to -3? Well, they have to be negative.

-2 + -1 = -3

What about the multiplication? A negative × a negative = a positive, so

-2 × -1 = 2

So your answer is

-2 and -1
6 0
4 years ago
ten people put there name into two different drawings. The first drawing is a trip to hawaii and the second is a new car. what i
kondor19780726 [428]

Answer:

unlikely

Step-by-step explanation:

thats alot of people

3 0
3 years ago
Today joelle walked at a rate of 3 miles per hour and she ran 15 minutes at a rate of 6 miles per hour.How many total miles did
svetoff [14.1K]
I added a screenshot with the complete question

<u><em>Answer:</em></u>
Total miles = 2.5 miles

<u><em>Explanation:</em></u>
<u>1- While walking:</u>
We are given that Joelle walked 20 minutes at a rate of 3 miles per hour.
This means that she walked \frac{20}{60} =  \frac{1}{3} of an hour at a rate of 3 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while walking:</u>
Distance = 3 * \frac{1}{3} = 1 mile

<u>2- While running:</u>
We are given that Joelle ran 15 minutes at a rate of 6 miles per hour
This means that she ran \frac{15}{60} =  \frac{1}{4} of an hour at a rate of 6 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while running:</u>
Distance = 6 * \frac{1}{4} = 1.5 miles

<u>3- getting the total mileage:</u>
Total distance she covered = distance while walking + distance while running
Total distance she covered = 1 + 1.5
Total distance she covered = 2.5 miles

Hope this helps :)

4 0
3 years ago
Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
A rectangle has vertices at these coordinates.
kompoz [17]
(6,2) is the fourth vertex
8 0
3 years ago
Read 2 more answers
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