Help me i need the right ansers plss

Simplify the slope of AC

Lemur [1.5K]

Answer:

$Slope\:\: \overline{AC} =1$

Step-by-step explanation:

A is on the same point on the x-axis as B and the same point on the y-axis as D

Therefore, the coordinate of A is (0,0)

C is on the same point on the x-axis as D and the same point on the y-axis as B.

Therefore, the coordinate of C is (a,a)

We are to determine the slope of the line joining A to C.

$Slope, m =\dfrac{y_2-y_1}{x_2-x_1} \\(x_1,y_1)=(0,0),(x_2,y_2)=(a,a)\\$Therefore, Slope of AC$\\m =\dfrac{a-0}{a-0}\\=\dfrac{a}{a}\\\\=1$

$Slope\:\: \overline{AC} =1$

6 0

3 years ago

A fair die with sides numbered 1, 2, 3, 4, 5, and 6 is to be rolled until a number greater than 4 first appears. what is the pro

AnnyKZ [126]

First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3

So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3

7 0

4 years ago

Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of

frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

3) $\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

4) $df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 21 37 58 116

Not Married 59 63 42 164

Total 80 100 100 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is $\alpha=0.05$

Part 2

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{80*116}{280}=33.143$

$E_{2} =\frac{100*116}{280}=41.429$

$E_{3} =\frac{100*116}{280}=41.429$

$E_{4} =\frac{80*164}{280}=46.857$

$E_{5} =\frac{100*164}{280}=58.571$

$E_{6} =\frac{100*164}{280}=58.571$

And the expected values are given by:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 33.143 41.429 41.429 116

Not Married 46.857 58.571 58.571 164

Total 80 100 100 280

And now we can calculate the statistic:

$\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0

4 years ago

In a certain year, there were 92 female officials in Congress, which is comprised of the House of Representatives and the Senate

crimeas [40]

Answer:

There are 78 female members of the House of Representatives and 14 female members of the Senate.

Step-by-step explanation:

Let h equal the amount of female members of the House of Representatives and s equal the amount of female members in the Senate.

Since the amount of female officials in Congress is 92, and is made up of the House of Representatives and the Senate, we can represent this as the equation h+s=92

Since there are 64 more female members in the House of Representatives than female Senators, the senators would need 64 more female members to have the same amount as the House of Representatives. We can represent this as h=s+64.

Substituting, we get s+64+s=92, which simplifies to 2s+64=92. Subtracting 64 from both sides, we get 2s=28, which equals to s=14. There are 14 female senators. Substituting back into h+s=92, 14+s=92, and s=78. Therefore, there are 78 female members of the House of Representatives and 14 female members of the Senate.

8 0

2 years ago

14^-3x14^5 using a single positive exponent

lesya692 [45]

Answer:

1/14^3x times 14^5

Step-by-step explanation:

Sorry I dont have one but I hope this helps, GodBless.

6 0

3 years ago

Read 2 more answers