All categories

2 years ago

Which of the following numbers belong to the set of complex numbers AND The set of imaginary numbers? Select all that apply.

1 answer:

7 0

<span>To be both complex and imaginary, the answer would have to include "i" as well as have the form "a + bi". The first example, 3i - 5, fits. This would look to be the only example that does fit. The negative square root of 14 would be imaginary, but not complex.</span>

You might be interested in

simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed

Gnoma [55]

Answer:

$\frac{x^{2} + 19x - 56}{4 {x}^{2} - 32x}$

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

$\frac{x + 7}{4x} + \frac{5}{x - 8}$

$= \frac{(x + 7)(x - 8)}{4x(x - 8)} + \frac{5(4x)}{4x(x - 8)}$

$= \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}$

$= \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4 {x}^{2} - 32x}$

7 0

2 years ago

What is the length of ef in the right triangle below?

katrin2010 [14]

Answer: A

Step-by-step explanation:

Using pythagoras;

$25 = \sqrt{7^{2}+ x^{2} }\\25^{2}=7^{2} +x^{2} \\625 = 49 +x^{2} \\576 = x^{2} \\x = 24$

Please give me a brainliest answer

3 0

2 years ago

Read 2 more answers

A quadrilateral with vertices at A(4, –4), B(4, –16), C(12, –16), and D(12, –4) has been dilated with a center at the origin. Th

erastova [34]

I think the answer is 3, because D(12;-4) and D' is (36;-12). Then 36/12=3, -12/-4=3
(I hope it's true)!!! :)

6 0

3 years ago

Read 2 more answers

Solve for C.<br> 5/4= -4c + 1/4

dybincka [34]

5/4= -4c + 1/4

Inverse operation

$\frac{5}{4} = -4c + \frac{1}{4}$

- 1/4 -1/4

5/4 - 1/4 = 4/4

$\frac{4}{4} = -4c$
-4c/-4 = 4/4 ÷ -4/1

4/4 *- 1/4 = c
-4/8 = c
c = -1/2

Answer: $c = - \frac{1}{2}$

6 0

2 years ago

Which is equivalent to (4xy-3x)^2, and what type of special product is it?

mars1129 [50]

It's not the difference of squares, rather it is the square of a difference. That leaves a perfect square trinomial, which narrows your selection to two choices. An expression with 2 terms is not a trinomial, so that further narrows your selection. The appropriate choice is

... (4xy -3z)² = 16x²y² -24xyz +9z², a perfect square trinomial

_____

The expression you have in your problem statement has no z term, so none of the choices is applicable to that one.

8 0

3 years ago

Read 2 more answers