All categories

3 years ago

Answer the following: 5 x (2)³

Mathematics

2 answers:

Ivenika [448]3 years ago

7 0

Answer:

Step-by-step explanation:

first find 2^3 which is 8

then 8*5 which is 40

dusya [7]3 years ago

3 0

Answer:

Step-by-step explanation:

5 x (2)³

PEMDAS says exponents first

5 x 8

Then multiply

You might be interested in

Tammy scored 88, 72, 44 points on her first three test. What must she score in her last test to get at least an average of 70?

lara [203]

Answer:

Step-by-step explanation:

(88+72+44+x)/4=70

88+72+44+x=280

204+x=280

x=76

Therefore, Tammy needs to score a 76 on her last test to get at least an average of 70.

5 0

3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

3 years ago

While bowling with friends, Brandy rolls a strike in 57 out of 72 frames. what is the experimental probability that brandy will

gogolik [260]

Answer:

79.17% probability that brandy will roll a strike the first frame of the next game

Step-by-step explanation:

The experimental probability is the probability based on previous outcomes, that is, the number of desired outcomes divided by the number of total outcomes.

While bowling with friends, Brandy rolls a strike in 57 out of 72 frames. What is the experimental probability that brandy will roll a strike the first frame of the next game?

Desired outcomes:

57 strikes

Total outcomes:

72 frames

Probability:

p = 57/72 = 0.7917

79.17% probability that brandy will roll a strike the first frame of the next game

3 0

3 years ago

You are cutting the small square patches to use to make a quilt . The size of the quilt is 60 inches by 72 inches . Find all the

kodGreya [7K]

Answer:

Step-by-step explanation:

one piece is 60×60 inch

5 pieces each measuring 12×12

so total 6 patches on one side and 6 pieces back side of same dimension.

5 0

3 years ago