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3 years ago

10

The perimeter of a rectangular chicken coop is 44 feet. The width is w feet and the length is w + 4 feet. What are the length an

d width of the coop?

1 answer:

Kaylis [27]3 years ago

8 0

Answer:

w = 9 ft

l = 13 ft

Step-by-step explanation:

2w + 2(w+4) = 44

simplify:

4w + 8 = 44

4w = 36

w = 9 ft

l = 13 ft

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

<u>Josh:</u>

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em> $h(t)=0$ <em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

I don't the graphing part of the homework

Katyanochek1 [597]

Problem 4-25
a. ii - Relation: When the latitude increases, the temperature decreases.
b. iv - Relation: all cars regardless of the weight goes at the same speed.
c. iii - Relation: No relationship
d. i - Relation: People with more expensive homes have more expensive cars.

System of Equations Part
You can plug these (x,y) values in one of the equations to see if it is true.
a. (1,2)
b. (0,-4)
c. (3,7)

7 0

3 years ago

(- 1, 2) and (9, - 3)

slava [35]

9/5

the distance is 9 over, and 5 up.

5 0

3 years ago

Read 2 more answers

Twelve more than half of a number is equal to the number

tester [92]

Let's consider that number to be 'x'..
So, twice the number (2x) is 12 greater than than the half of the number.
So the equation will be like,
2x=12+x/2
Solving this further,
2x=(24+x)/2
=> 4x=24+x
=>4x-x=24
=>3x=24
=>x=8..
So the number is "8".

5 0

2 years ago

I believe the answer is C. however, I'm not 100% sure.

Brut [27]

The answer would be C. You’re correct! Because there are 3 blue marbles @ $1 each that amounts to a possible $3 gain for Mark. Evan has the chance to get $4. Cayla also can make $3 like Mark.

7 0

2 years ago