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gladu [14]
3 years ago
15

Whats the RIGHt answer giving brainliest

Mathematics
1 answer:
Murrr4er [49]3 years ago
4 0

Answer:

A

Step-by-step explanation:

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Helppppp i dont know pslßss​
Natali5045456 [20]

Answer:

width=3

Step-by-step explanation:

area=length X width

length=4 X width

=>area=4 X width X width

=>area=(2 X width)^2

=>36=(2 X width)^2

=>6=2 X width

=>width=3

5 0
3 years ago
Read 2 more answers
Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ
In-s [12.5K]
PART A

The equation of the parabola in vertex form is given by the formula,

y - k = a {(x - h)}^{2}

where

(h,k)=(1,-2)

is the vertex of the parabola.

We substitute these values to obtain,


y  + 2 = a {(x - 1)}^{2}

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.


6  + 2 = a {(3 - 1)}^{2}


8= a {(2)}^{2}


8=4a


a = 2
Hence the equation of the parabola in vertex form is


y  + 2 = 2 {(x - 1)}^{2}


PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

y  + 2 = 2{(x - 1)}^{2}

This implies that

y + 2 = 2(x - 1)(x - 1)


We expand to obtain,


y + 2 = 2( {x}^{2}  - 2x + 1)


This will give us,


y + 2 = 2 {x}^{2}  - 4x + 2


y =  {x}^{2}  - 4x

This equation is now in the form,

y = a {x}^{2}  + bx + c
where

a=1,b=-4,c=0

This is the standard form
7 0
3 years ago
Solve the system of equations.
Sloan [31]

Answer:

b.

( -3, -5)

Step-by-step explanation:

6x + 13 = 2x + 1

6x -2x = 1-13

4x = -12

x = -12/4 = -3

y = 6x + 13

y = 6(-3) +13 = -18+13 = -5

(x, y) = (-3,-5)

7 0
3 years ago
Read 2 more answers
Write a recursive rule for the sequence.<br><br> 7, 6, 13, 19, 32, ...
Zinaida [17]

Answer:

Step-by-step explanation:

+7-1

4 0
3 years ago
Write the common rule to describe the translation using coordinate notation.
UNO [17]

The common rule is (x - 1, y + 3) can be used to describe the translation.

Step-by-step explanation:

Step 1:

The point J (-3, -4) becomes J^{1} (-4, -1).

In order to write the rule for translation from J to J^{1}, we subtract the x coordinate of J from J^{1} and subtract the y coordinate of J from J^{1}.

The x coordinate = -4-(-3) = -4+3 = -1.

The y coordinate = -1-(-4) = -1+4 = 3.

Step 2:

So from the calculations, we get that the x coordinate is subtracted by 1 i.e. x-1 and the y coordinate is increased by 3 i.e. y+3.

So the common rule is (x - 1, y + 3).

4 0
3 years ago
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