Answer:
A) 40000
Step-by-step explanation:
this is the answer to your question
Domain is the entire span left to right (on the x-axis) that the graph is on. Since the graph goes from x=-4 and ends at x=4, the domain would be from -4 to 4. The circle at -4 is open, so it does not include the point at -4, just everything leading up to it. So, the domain would be

The range is similar, it is the entire span that the graph goes up and down (on the y-axis). The graph starts at the bottom at y=-2, and ends at y=5. The bottom point (4,-2) is closed, so the graph includes that point, and the top point (-4,5) is open and doesn't include the point. Therefore, the range would be

The -4 will translate the graph of f(x) 4 units to the right.
Then the -2 before the x will stretch it vertically with factor 2, then reflect it in the y -axis.
Finally the + 5 will translate the graph 5 units vertically upwards
Answer:
A = -1
So, option (B) is the correct answer.
Step-by-step explanation:
The two points on line have coordinates: p (x₁, y₁) = (0, A) and q(x₂, y₂) = (2 , -3)
Slope of line = A
Slope of line = 
Now since the slope of line is A and its has two coordinates (0, A) and (2 , -3), ∴






So, option (B) is the correct answer.