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rosijanka [135]
3 years ago
10

Fred the clown can create 20 animal balloons every 15 minutes​

Mathematics
2 answers:
mario62 [17]3 years ago
8 0
Yes so what would be his time limit or how much does he need to make?
iVinArrow [24]3 years ago
5 0

Answer:

Wow that's cool. What's the question here?

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kipiarov [429]

Answer:

              s

_______________

ls^4 + 32ls^2 + 256l

Step-by-step explanation:

I used an algebra calculator called MathPapa to solve your equation.

Also, welcome to brainly!

7 0
2 years ago
Please help. I need it. Bad.
Murljashka [212]

Answer:

Option a.

Step-by-step explanation:

In the given triangle angle A is a right angle so triangle ABC is a right angled triangle.

Opposite side of right angle is hypotenuse. So, CB is hypotenuse.

From figure it is clear that CA is shorter that segment BA.

All angles are congruent to itself. So angle C is congruent to itself.

We know that, if an altitude is drawn from the right angle vertex in a right angle triangle it divide the triangle in two right angle triangles, then given triangle is similar to both new triangles.

So, triangle ABC is similar to triangle DBA if segment AD is an altitude of triangle ABC.

Therefore, the correct option is a.

3 0
3 years ago
Can you please help with adjacent angles?
mojhsa [17]
Adjacent angles are angles that have a common side and a common vertex. The only one that fits this would be <FEC and <FEH because it shares the side of FE and common vertex of E. I hope this helps you. :)
4 0
3 years ago
Kennedy spins the pointer of a spinner. The spinner has four equal sections labeled 1 to 4.
Mazyrski [523]

Answer:

1 or 4/4

It is certain that the spinner will land on a number less that 5 because the selections are labeled 1 to 4 and the numbers 1 to 4 are less than 5.

3 0
3 years ago
Which congruence criteria can be used directly from the information about triangles HIJ and MNO to prove IJ¯¯¯¯¯¯≅MN¯¯¯¯¯¯¯¯¯¯ b
skelet666 [1.2K]

Answer: \overline{IJ}\cong \overline{MN}

Step-by-step explanation:

Given: In triangle HIJ and triangle MNO we have

\overline{HI}\cong \overline{NO}, \angle{I}\cong \angle{N} ,\angle{H}\cong \angle{O}

here, HI and NN are the included side between  ∠I & ∠H and ∠N and ∠O.

So , by ASA congruence rule,

ΔHIJ ≅ ΔMNO

So by CPCTC  (corresponding parts of the congruent triangles are congruent)

\overline{IJ}\cong \overline{MN}

7 0
3 years ago
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