What exspession is the value of 2/3

0.9 (13) - 1.7 (3) =

marissa [1.9K]

Answer:

6.6

Step-by-step explanation:

8 0

3 years ago

To earn a fitness award, your average heart rate while walking must be between 80 and 89 beats per minute, inclusive. Suppose yo

Anika [276]

Answer:

84

Step-by-step explanation:

hope this helps

5 0

3 years ago

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Find the slope of the line which goes through the given points.<br> d<br> A(2,8) and B(2,6)

KATRIN_1 [288]

Answer:

Undefined

Step-by-step explanation:

A slope is found using the formula rise (change in y) over run (change in x). The change in x is 0, and the change in y is -2. The answer is -2/0, but dividing by 0 gives you undefined. Don't believe me? Look at the attached image.

Hope this helps!

7 0

3 years ago

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Suppose that A and B are points on the number line.

oksian1 [2.3K]

Answer:

Suppose that A and B are points on the number line.

If AB=11 and A lies at 6, where could B be located?

If there is more than one location, separate them with commas

Step-by-step explanation:

Suppose that A and B are points on the number line.

If AB=11 and A lies at 6, where could B be located?

If there is more than one location, separate them with commas

4 0

3 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0

3 years ago