Knowing that a quadratic equation has two possible solutions, we need to be careful when we solve exponential equations in checking for any quadratic one that appears. Due to 2 possible solutions,
Hope I helped :)
Think of it like this
4x=2x+6
subtract two from 4
2x=6
x=3
A
substitute each point into the inequality and check validity of solution
A (4, 4)
4 ≤ 16 - 12 + 2 ⇒ 4 ≤ 6 → True hence valid solution
B (3, 3 )
3 ≤ 9 - 9 + 2 ⇒ 3 ≤ 2 → False hence not valid
C (1, 1 )
1 ≤ 1 - 3 + 2 ⇒ 1 ≤ 0 → False hence not valid
D (2, 2 )
2 ≤ 4 - 6 + 2 ⇒ 2 ≤ 0 → False hence not valid
Okay -
So, the goal when we have an equation is to find the value of the variable. So, let's isolate that variable on <em>one </em>side of the equation!
<em>* original equation </em>
<em>5x + 4 = 49.
</em><em>* subtract four from both sides. if you do something on one side of the equation, you have to do it on the other.
</em><em>5x + 4 - 4 = 49 - 4.
* now we are going to divide 5 on both sides to isolate x.
5x/5 = 45/5.
* and our answer is...
x = 9. =)
</em>
Answer:
Step-by-step explanation:
The average cost for the training session provided he is a sports trainer can be computed as follows:
Let's assume that;
average cost = C(x)
the no. of session = x
Then:
Now, suppose the trainer wants the average cost C(x) to drop below $16;
Then, we have the following function:
By cross multiply:
120 + 15x ≤ 16x
120 ≤ 16x - 15x
120 ≤ x
Therefore, the required no. of session, if the average cost should drop below $16, is 120.
