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Andreyy89
3 years ago
7

The smaller arrow is a scale drawing of the larger arrow. What percent of the area of the larger arrow is the area of

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0

Answer:

the answer is 43%

Step-by-step explanation: The answer is 43 and if you look up on you will find it because i know the answer

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The least common denominator of two fractions is 28. If you subtract the two denominators, their difference is 10. What are the
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14 and 28 are two different common denominators for the fractions and  we convert both fractions to eighteenths we can subtract 3 eighteenths from 10

so what do you think the answer is
this is just a example
7 0
3 years ago
PLEASE HELP WILL GIVE BRAINLY POINTS!!!!
Afina-wow [57]

Conner played a total of  6 +3 + 6 = 15 games. He won or tied 6+ 3 = 9 games.

His percentage is 9/15 = 0.6 x 100 = 60%

April played 5+7+4 = 16 games and won or tied 5 +7 = 12 games.

Her percentage is: 12/16 = 0.75 x 100 = 75%

Tony played 20 games and won or tied 14.

His percentage is: 14/20 = 0.7 x 100 = 70%

April has the highest percentage so she is the one who should play.

8 0
3 years ago
Solve the equation x/4+3=-6
charle [14.2K]
X/4 = -9

x/4 = -9/1

cross multiply 

x = -36
3 0
3 years ago
The diameter of steel rods manufactured on two different extrusion machines is being investigated. Two random samples of sizes
devlian [24]

Answer:

(a) There is no evidence to support the claim that the two machines produce rods with different mean diameters.

P-value is 0.818

(b) 95% confidence interval for the difference in mean rod diameter is (-0.17, 0.27).

This interval shows that the difference in mean is between -0.17 and 0.27.

Step-by-step explanation:

(a) Null hypothesis: The two machines produce rods with the same mean diameter.

Alternate hypothesis: The two machines produce rods with different mean diameter.

Machine 1

mean = 8.73

variance = 0.35

n1 = 15

Machine 2

mean = 8.68

variance = 0.4

n2 = 17

pooled variance = [(15-1)0.35 + (17-1)0.4] ÷ (15+17-2) = 11.3 ÷ 30 = 0.38

Test statistic (t) = (8.73 - 8.68) ÷ sqrt[0.38(1/15 + 1/17)] = 0.05 ÷ 0.218 = 0.23

degree of freedom = n1+n2-2 = 15+17-2 = 30

Significance level = 0.05 = 5%

Critical values corresponding to 30 degrees of freedom and 5% significance level are -2.042 and 2.042.

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.23 falls within the region bounded by the critical values -2.042 and 2.042.

There is no evidence to support the claim that the two machines produce rods with different mean diameters.

Cumulative area of test statistic is 0.5910

The test is a two-tailed test.

P-value = 2(1 - 0.5910) = 2×0.409 = 0.818

(b) Difference in mean = 8.73 - 8.68 = 0.05

pooled sd = sqrt(pooled variance) = sqrt(0.38) = 0.62

Critical value (t) = 2.042

E = t×pooled sd/√n1+n2 = 2.042×0.62/√15+17 = 0.22

Lower limit of difference in mean = 0.05 - 0.22 = -0.17

Upper limit of difference in mean = 0.05 + 0.22 = 0.27

95% confidence interval for the difference in mean rod diameter is between a lower limit of -0.17 and an upper limit of 0.27.

3 0
3 years ago
Carrie oakey has only nickles to spend at the fair. She buys 3 tickets for 50 cents each and has $.40 left over. How many coins
Nat2105 [25]

Answer:

she had 18 nickles

Step-by-step explanation: your so welcome

7 0
3 years ago
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