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MakcuM [25]
3 years ago
6

Help asap please!!!!

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0
(4,-3) I believe- I got it bc x1 is 3 away from x2 and same with y1 and y2
You might be interested in
Select all the expressions equivalent to: (4^5)⋅4^3 Group of answer choice 2^14 4^12 2^16 16^8 4^8 16^4
kumpel [21]

Answer:

Choices given as 2^{16}, 4^8 and 16^4 are correct.

Step-by-step explanation:

Given expression is,

(4^5)(4^3)

By applying law of exponents in the given expression,

(4^5)(4^3)=4^{5+3}

            =4^8

(4^5)(4^3)=(2^2)^5(2^2)^3

            =(2^{2\times 5})(2^{2\times 3})

            =2^{10}\times 2^6  

            =2^{16}

            =(2^4)^4

            =(16)^4

Therefore, choices given as 2^{16}, 4^8 and 16^4 are correct.

4 0
2 years ago
Given: m
marissa [1.9K]

Answer:

m∠LTE = 110

Step-by-step explanation:

1. add up all of the arcs.

2x+3x+4x-8+x-12

2. all of the arcs equal 360

2x+3x+4x-8+x-12=360

3. Find x

10x-20=360, x=38

4. angle LTE is equal to half of the sum of the intercepted arcs.

0.5(arc LE +GF)

5. plug in LE +GF with x

.5(76+144)

7 0
3 years ago
Read 2 more answers
What are the coordinates of the point?
kenny6666 [7]
D -2, 4 is in the second quadrant because the -x brings it to the left side and the positive 4 puts it in the upper of the left side which is the second quadrant
7 0
3 years ago
Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
5 0
3 years ago
Read 2 more answers
Please help me! 17 / 13 - 3 / 2
zhenek [66]
Point two should be your answer
8 0
3 years ago
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