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JulsSmile [24]
3 years ago
10

Can someone give me the answer to this please?

Mathematics
2 answers:
andre [41]3 years ago
7 0

Answer:

ok so its C bc 8 x 0.5 = 4 and so there are 4 long rectangles so multiply by 4 which is 16 bc 4 x 4 = 16 next find the area of the 2 squares 0.5 x 0.5 =0.25

multiply that by 2 because there are 2 squares which is 0.5 and so

16+0.5= 16.5 in²

Step-by-step explanation:

GalinKa [24]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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Line MN passes through points M(4, 3) and N(7, 12). If the equation of the line is written in slope-intercept form, y = mx + b,
seropon [69]

Answer:

-9

Step-by-step explanation:

What b represents here is the y intercept.

The first thing we will do here is to find the slope.

Mathematically;

m = (y2-y1)/(x2-x1)

Plugging the values;

m = (12-3)/(7-4) = 9/3 = 3

The equation can thus be written as;

y = 3x + b

To get b, we can use any of the points since they lie on the line

Let’s use point M

Substitute the values of x and y in the equation

3 = 3(4) + b

3 = 12 + b

b = 3-12 = -9

3 0
3 years ago
Read 2 more answers
N-4n=-9+6n<br> A) (-9)<br> B) (1)<br> C) (All real numbers. }<br> D) (14)
xeze [42]
The answer is B I hope you get it.
6 0
3 years ago
Find the value of x.<br><br> log 3 x = 4<br><br> A.) 7<br> B.) 12<br> C.) 27<br> D.) 81
lakkis [162]

Hello from MrBillDoesMath!

Answer:

Choice D, 81

Discussion:

By log 3x = 4 I presume that "3" is the base not a multiplier of x. Assuming it is the base, then the equation is equivalent to

x = 3^4

  = 81

This is Choice D.


Thank you,

MrB

8 0
3 years ago
PLEASE HELP ME WITH 9,10 AND 11 THANKS!!!!
Stella [2.4K]
Subtract easy money your welcome
4 0
3 years ago
F(x)= x(x+3)(x+1)(x-4) has zeros at x=-3
anygoal [31]

Answer:  C) Sometimes positive; sometimes negative

============================================================

Explanation:

Pick a value between x = -1 and x = 0. Let's say we go for x = -0.5

Plug this into f(x)

f(x) = x(x+3)(x+1)(x-4)

f(-0.5) = -0.5(-0.5+3)(-0.5+1)(-0.5-4)

f(-0.5) = -0.5(2.5)(0.5)(-4.5)

f(-0.5) = 2.8125

We get a positive value.

This shows that f(x) is positive on the region of -1 < x < 0

----------------

Now pick a value between x = 0 and x = 4. I'll use x = 1

f(x) = x(x+3)(x+1)(x-4)

f(1) = 1(1+3)(1+1)(1-4)

f(1) = 1(4)(2)(-3)

f(1) = -24

Therefore, f(x) is negative on the interval 0 < x < 4

----------------

In short, f(x) is both positive and negative on the interval -1 < x < 4

It's positive when -1 < x < 0

And it's negative when 0 < x < 4

4 0
1 year ago
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