Answer:
74.0°
Step-by-step explanation:
In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree
Solution:
A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.
Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:
In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.
Using sine rule, we can find ∠K:
North is the direction of positive y-axis. East is the direction of positive x-axis. So West will be the direction of negative x-axis.
Northwest will mean, in between north and west i.e. in between y-axis and the negative x-axis which is the mid of the 2nd quadrant. Thus the vector pointing northwest will form an angle of 135 degrees with positive x-axis.
The magnitude of unit vector is 1 and is forming an angle of 135 degrees. In terms of its components, we can write:
x-component = 1 cos (135) =
y-component = 1 sin (135) =
Thus the unit vector will be =
In vector form, component form the vector can be written as:
7,676 rounded to the nearest hundredth is: 7,700.
You are focusing on the 7676. If the 7 on the right of it has a number below five, then it would be 7600. On this hand, with it being more than 5, the correct answer is 7,700.
83 degrees. corresponding angles are congruent
the SAS similarity theorem
