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Dmitriy789 [7]
3 years ago
6

ANSWER ASAP!! WILL MARK BRAINLIEST!

Mathematics
1 answer:
ra1l [238]3 years ago
4 0

Answer:

1 and 3

Step-by-step explanation:

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riley larue ran a 100 yard dash at a speed of 56.8 feet per second on Oct. 5, 2009. Convert his speed to miles per hour
Serggg [28]
56.8 feet per second = ? miles per hour

5280 feet = 1 mile
3600 sec = 1 hour

56.8/5280 = 0.01075 miles/second

(0.01075 miles/second)*(3600 seconds) = 38.72727 miles per hour
7 0
4 years ago
The weight of Kyle's dog increased from 29.7 pounds to 48.9 pounds in an 8 month period. What was the average weight increase pe
Damm [24]

Answer:

per month means we divide by the months

here is our formula

we do 48.9-29.7 to see the increase, and divide by the months to see how much per month

(48.9-29.7)/8

We get 2.4, meaning the average weight increase per month is 2.4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is 41:15 simplified
Alex787 [66]

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator

GCD of 41 and 15 is 1

Divide both the numerator and denominator by the GCD

41 ÷ 1

15 ÷ 1

Reduced fraction:

41

15

Therefore, 41/15 simplified to lowest terms is 41/15.

4 0
3 years ago
Pic below...........<br> ..............<br> look below
Kipish [7]

Answer:

3

Step-by-step explanation:

Factor the numerator and denominator and cancel the common factors.

7 0
4 years ago
Read 2 more answers
Let f(x) = 13 - |2x+ 1|. Find all x for which f(x) less than or equal to 14
Art [367]

Answer:

x \leqslant -1\: or \: x  \geqslant  - 1

Step-by-step explanation:

The given function is

f(x) = 13 -  |2x + 1|

We want to find all values of x for which:

f(x) is greater than or equal to 14.

This implies;

13 -  |2x + 1|  \geqslant 14

Subtract 13 from both sides;

-  |2x + 1|  \geqslant 14 - 13

|2x + 1|  \geqslant - 1

By definition of the absolute value function,

- (2x + 1) \geqslant  - 1 \: or \: (2x + 1) \geqslant  - 1

Divide through the first inequality and and reverse the inequality sign:

2x + 1 \leqslant -1 \: or \: 2x + 1 \geqslant  - 1

2x \leqslant -1  - 1 \: or \: 2x  \geqslant  - 1  - 1

2x \leqslant -2 \: or \: 2x  \geqslant  - 2

x \leqslant -1\: or \: x  \geqslant  - 1

8 0
4 years ago
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