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3 years ago

11

The Science Club went on a two-day field trip. The first day the members paid $30 for transportation plus $10 per ticket to the

planetarium. The second day they paid $100 for transportation plus $7 per ticket to the geology museum. Write an expression to represent the total cost in dollars for two days for the n members of the club.
An expression that represents the total cost in dollars for two days for the n members of the club is given by

2 answers:

Brilliant_brown [7]3 years ago

7 0

Answer:

just add all the numbers which means $147

sashaice [31]3 years ago

3 0

Answer: I believe is $147 because u have to add all the number and it will give u the total of 147. So the total cost in dollars for two days for the n members of the cub will be $147.

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Solve for d. 1.2+d+0.4=9.7

Advocard [28]

Move everything around. d+1.6=9.7. d=8.1.

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3 years ago

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Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam

MariettaO [177]

$X-(A\cup B)=(X-A)\cap(X-B)$

I'll assume the usual definition of set difference, $X-A=\{x\in X,x\not\in A\}$ .

Let $x\in X-(A\cup B)$ . Then $x\in X$ and $x\not\in(A\cup B)$ . If $x\not\in(A\cup B)$ , then $x\not\in A$ and $x\not\in B$ . This means $x\in X,x\not\in A$ and $x\in X,x\not\in B$ , so it follows that $x\in(X-A)\cap(X-B)$ . Hence $X-(A\cup B)\subset(X-A)\cap(X-B)$ .

Now let $x\in(X-A)\cap(X-B)$ . Then $x\in X-A$ and $x\in X-B$ . By definition of set difference, $x\in X,x\not\in A$ and $x\in X,x\not\in B$ . Since $x\not A,x\not\in B$ , we have $x\not\in(A\cup B)$ , and so $x\in X-(A\cup B)$ . Hence $(X-A)\cap(X-B)\subset X-(A\cup B)$ .

The two sets are subsets of one another, so they must be equal.

$X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)$

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices $i\in I$ .

Proof of one direction for example:

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3 years ago

There are 68 apples in the school kitchen. The school needs 130 apples for all the students in grade 2. The school gets two boxe

WITCHER [35]

Answer:No they do not have enough they only have 82 apples

Step-by-step explanation:

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3 years ago

The answers ? Plssss I’ll mark u brianliest

frez [133]

Answer:

4. C

5. B

Step-by-step explanation:

4. Circumference = diameter * pi

pi is approximately 3.14

Diameter = 2*radius

Diameter = 2*8 = 16

Circumference = 3.14 (16), so the answer is C.

5. The question asking asking for the surface of the toy box.

Surface area of a cube = 6*the area of one face of the cube = 6 (edge * edge)

Substitute the edge with 2

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Surface area is 24 feet squared, so the answer is B

Hope this helps :)

Have an awesome day!!

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2 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

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3 years ago