Answer:
20 times
Step-by-step explanation:
Here is a chart:
3,13,23,30,31,32,33,34,35,36,37,38,39,43,53,63,73,83,93.
It appears 20 times. Hope this helps!
The answer can be readily calculated using a single variable, x:
Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%
The problem is then stated as:
(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000
Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
Answer:
-34b4
Step-by-step explanation:
Since the variables are the same b4, you just add the constants (-16 & -18).
The inequality can be:
Now you divide both sides by 150 to get the #of boxes.
Lastly, x is 20. So the maximum amount of boxes that the freight elevator can hold is 20
