Jen received 60% on her science quiz.She got 9 question correct.How many total questions were on the science test
1 answer:
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To me personally, the first bit f(g(x)) is easy and the domain is tricky. Let's try explain this.
A function takes an input number and returns an output number depending on the function. Look at f(x) = x+3, if we let the input number be 2 then we say that f(2) = 5. We could do f(π) to give us π+3 or even f(x²) to give us x² +3. The trick is to substitute the input into the function equation.
You have been asked to find f(g(x)). You know f(x) =
. Putting numbers in at this point would be easy (try work out f(2), you'll do it really quick) but you have to put in g(x).
f(g(x)) =
we also know that g(x) =
so we can say that
f(g(x)) =
and that is f(g(x)) but the question requires that we simplify it so
f(g(x)) =
Now for the tricky bit (for me, at least). The domain is the full set of values that you can 'put in to' the function and still get a real value out. So how do we work out what numbers 'break' the function? I like to use the fact that DIVIDING BY ZERO IS IMPOSSIBLE. What value of x can we put into the function to make it so the function is being divided by 0? i.e. 1-2x = 0 solve that and you have a value of x that isn't part of the domain.
This means the domain is all real numbers EXCEPT the solution to that equation. (Because if we put that value into f(g(x)) it's impossible to get a value out.)
[I know this was a lot to read, if you have any questions or don't get anything feel free to message me or leave a comment.]
A function takes an input number and returns an output number depending on the function. Look at f(x) = x+3, if we let the input number be 2 then we say that f(2) = 5. We could do f(π) to give us π+3 or even f(x²) to give us x² +3. The trick is to substitute the input into the function equation.
You have been asked to find f(g(x)). You know f(x) =
f(g(x)) =
we also know that g(x) =
f(g(x)) =
f(g(x)) =
Now for the tricky bit (for me, at least). The domain is the full set of values that you can 'put in to' the function and still get a real value out. So how do we work out what numbers 'break' the function? I like to use the fact that DIVIDING BY ZERO IS IMPOSSIBLE. What value of x can we put into the function to make it so the function is being divided by 0? i.e. 1-2x = 0 solve that and you have a value of x that isn't part of the domain.
This means the domain is all real numbers EXCEPT the solution to that equation. (Because if we put that value into f(g(x)) it's impossible to get a value out.)
[I know this was a lot to read, if you have any questions or don't get anything feel free to message me or leave a comment.]
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
This is the equation of a vertical parabola open upwards
The vertex is a minimum
The vertex is the point (1,2)
The y-intercept is the point (0,3)
The function does not have x-intercepts
see the attached figure
Answer: the height of the pole is 16.1 m.
Step-by-step explanation:
The scenario is illustrated in the attached photo.
x represents the height of the pole.
y represents the distance from the foot of one stabilizing wire to the foot of the pole.
30 - y represents the distance from the foot of the other stabilizing wire to the foot of the pole.
In solving the triangles, we would apply the tangent trigonometric ratio which is expressed as
Tan θ, = opposite side/adjacent side.
Considering triangle ACD,
Tan 60 = x/y
x = ytan60 = y × 1.732
x = 1.732y- - - - - - - - -1
Considering triangle BCD,
Tan 38 = x/(30 - y)
x = (30 - y)tan38 = 0.781(30 - y)
x = 23.43 - 0.781y- - - - - - - - -2
Substituting equation 1 into equation 2, it becomes
1.732y = 23.43 - 0.781y
1.732y + 0.781y = 23.43
2.513y = 23.43
y = 23.43/2.513
y = 9.3
x = 1.732y = 1.732 × 9.3
x = 16.1 m
