Answer:
27/10
2.7
Step-by-step explanation:
im not sure if that is the answer but that what i got
hope it helped
Ans is 392 mm and approx 400mm as perimeter of semi circle is pi r which is 22/7*16 + 40 mm which is the total of the two side of the triangle given.
I hope this will help you
Answer:
The required probability is 0.927
Step-by-step explanation:
Consider the provided information.
Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course.
That means 95% of students didn't enrolled in SAT prep course.
Let P(SAT) represents the enrolled in SAT prep course.
P(SAT)=0.05 and P(not SAT) = 0.95
30% of the SAT prep students were admitted to their first choice college, as were 20% of the other students.
P(F) represents the first choice college.
The probability he didn't take an SAT prep course is:
![P[\text{not SAT} |P(F)]=\dfrac{P(\text{not SAT})\cap P(F) }{P(F)}](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%3D%5Cdfrac%7BP%28%5Ctext%7Bnot%20SAT%7D%29%5Ccap%20P%28F%29%20%7D%7BP%28F%29%7D)
Substitute the respective values.
![P[\text{not SAT} |P(F)]=\dfrac{0.95\times0.20 }{0.05\times0.30+0.95\times0.20}](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%3D%5Cdfrac%7B0.95%5Ctimes0.20%20%7D%7B0.05%5Ctimes0.30%2B0.95%5Ctimes0.20%7D)
![P[\text{not SAT} |P(F)]\approx0.927](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%5Capprox0.927)
Hence, the required probability is 0.927
The formula for circumference is 2 x PI x r
Using the circumference we can find the radius:
50.24 = 2 x PI x r
Multiply 2 by PI:
2 x 3.14 = 6.28
50.24 = 6.28 x r
Divide both sides by 6.28:
R = 50.24 / 6.28
R = 8
The radius is 8 units.
Answer:
x = 98 degrees
Step-by-step explanation:
A heptagon has a total of 900 degrees for the interior angles. Add up all the angles and then subtract from 900 to find x.
146+122+142+140+110+142 = 802.
900-802 = 98