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3 years ago

The fourth grade class is taking a field trip. If there are 391 fourth graders and

Mathematics

1 answer:

Effectus [21]3 years ago

4 0

Answer:

Step-by-step explanation:

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If 0 lies in the quadrant IV. What can be the value of cos 0?

Andru [333]

Answer:

Positive one

Step-by-step explanation:

The angle 0 does not lie in any of the four quadrants, it lands directly in between quadrants I and IV. The value of cos 0 is always 1.

4 0

3 years ago

N + 7 < -3<br><br> solve and show work please

Hitman42 [59]

Answer:

n < -10

Step-by-step explanation:

In order to get the variable n by itself subtract 7 from both sides across the inequality

n + 7 < -3

-7 -7

n < -10

4 0

3 years ago

If a=2^3 x 3^7 x 5^3 x 11^4 and b= 2^2 x 3^5 x 7^2 x 11 x 13 , find the following:

Natalka [10]

Answer:

10,692

Step-by-step explanation:

GCF stands for Greatest Common Factor.

The way to find it is easy once you have the prime decomposition.

Search for common factors in the decomposition and take the least power, then multiply them all.

So, in our case, as the numbers are already broken down into prime factors , we have

$GFC(a,b)=2^2.3^5.11=10,692$

5 0

3 years ago

Allison is offered an annual salary of $24,500. What would be her biweekly gross pay? (Round to the nearest cent.) A. $2,041.67

bixtya [17]

Answer:

Option (B) is correct.

Allison biweekly gross pay is $942.31

Step-by-step explanation:

Given annual salary offered to Allison = $24,500.

We have to calculate Allison biweekly pay that is pay Allison got for 2 weeks

To calculate biweekly we first find Allison weekly pay then multiply it by 2.

We know there are 52 weeks in a year.

So, weekly salary offered to Allison $=\frac{24500}{52}=471.15$ (approx)

Biweekly salary will be = 2 × weekly salary

= 2 × 471.15

= 942.307(approx)

Thus, Allison biweekly gross pay is $942.31

6 0

3 years ago

Read 2 more answers

Answer true or false for 1-10 (picture above)

Softa [21]

$\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a+b}\leq\sqrt{a}+\sqrt{b}\\\\\sqrt{a-b}\geq\sqrt{a}-\sqrt{b}\\----------------------\\1)\ \sqrt{72}=\sqrt{9\cdot8}=\sqrt{9}\cdot\sqrt{8}\qquad TRUE\\\\2)\ \sqrt{13-5}=\sqrt{13}-\sqrt5\qquad FALSE\\\\3)\ \sqrt{9\cdot10}=\sqrt9+\sqrt{10}\qquad FALSE\\\\4)\ \sqrt{18bx}=\sqrt{18}\cdot\sqrt{b}\cdot\sqrt{x}\qquad TRUE\ if\ b\geq0\ and\ x\geq0\\\\5)\ \sqrt{8\cdot12}=\sqrt8\cdot\sqrt{12}\qquad TRUE\\\\6)\ \sqrt{m+x}=\sqrt{m}+\sqrt{x}\qquad FALSE$

$7)\ \sqrt{100+64}=\sqrt{100}+\sqrt{64}\qquad FALSE\\\\8)\ \sqrt{30}=\sqrt{5\cdot6}=\sqrt5\cdot\sqrt6\qquad TRUE\\\\9)\ \sqrt{44}=\sqrt{22+22}=\sqrt{22}+\sqrt{22}\qquad FALSE\\\\10)\ \sqrt{10\cdot10}=\sqrt{10}\cdot\sqrt{10}\qquad TRUE$

3 0

3 years ago