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Artist 52 [7]
3 years ago
9

The fourth grade class is taking a field trip. If there are 391 fourth graders and

Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

4

Step-by-step explanation:

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BRAINLIESTTTTTT ASAPPPP<br> PLEASE ANSWER MY QUESTION
yawa3891 [41]
The red line is represented by y ≥ -3x + 3.

The blue line is represented by y < 3/2x - 6.

A) In this system of inequalities, there is one solid line and one dashed line.

The solid line is the inequality y ≥ -3x + 3 because it has the symbol greater than or equal to. The "equal to" part of the symbol is important because it means that any coordinate located on the solid line is a solution.

However, the inequality y < 3/2x - 6 is a dashed line because it does not have "equal to." This makes the inequality a dashed line which means that all coordinates on it will not be a solution to the inequality.

In the inequality y ≥ -3x + 3, the shading is above the line. This means that all coordinates within the line and shaded area above the line will be a solution to the inequality.

In the inequality y < 3/2x - 6, the shading is below the line. This means that all coordinates within the shared area of the line will be a solution to the inequality. However, since y is not less than or EQUAL TO, all coordinates within the dashed line is not a solution to the inequality.

The solution area, where a coordinate is a solution to
both inequalities, is where the shaded areas of both inequalities overlap.

B) The point (-6, 3) is a not solution to both of the inequalities because it is not within the shared areas of the two inequalities.

Substitute the coordinate (-6, 3) in the inequality y < 3/2x - 6.

y < 3/2x - 6

3 < 3/2(-6) - 6

3 < -9 - 6

3 < -15

This is not true because a negative number cannot be greater than a positive number. Therefore, this proves that the coordinate (-6, 3) is not a solution for the inequality y < 3/2x - 6.

Check if the coordinate fits for the other inequality.

y ≥ -3x + 3

3 ≥ -3(-6) + 3

3 ≥ 18 + 3

3 ≥ 21

This is also not true because 3 is not greater than or equal to 21. Therefore, this coordinate is not a solution to the inequality y ≥ -3x + 3.

The coordinate (-6, 3) is not a solution for the system of inequalities because it is not a solution for both inequalities.

7 0
3 years ago
a pair of socks costs $5.00. a package of 3 pairs costs $12.00. how much would you save if you buy 2 packages instead of 6 indiv
svp [43]
you will save 6 dollars If you buy 2 packages, instead if 6 individual pairs.
7 0
3 years ago
PLS HELP I NEED HELP NOW<br> I BEG
stepan [7]
Hello there! The area of the triangle portion is 11 square units, the area of the rectangle portion is 77 square units, and the area of the entire figure is 88 square units.

To find the area of the triangle, we can follow the formula:

A = LW/2 (which means length x width divided by 2)

Given the formula:

2 • 11 = 22

22 divided by 2 gives us 11 square units.

To find the area of the rectangle portion, we can follow the area formula:

A = LW (which means area = length x width)

Given the formula:

7 • 11 = 77 square units

To find the area of the whole figure, we add the areas of both isolated shapes:

11 + 77 = 88 square units.

Therefore, our area for the entire figure is 88 square units. If you need any extra help, let me know and I will gladly assist you.
7 0
1 year ago
The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}

A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}

Now, comparing areas:

\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

7 0
3 years ago
TIMED!! please help me find the measure of angle 5, 6, and 7
Lisa [10]

Answer:

Description

Step-by-step explanation:

5 = 47, vertical angles

6 = 74, triangle interior angles add up to 180

7 = 59, linear pairs add up to 180

8 0
3 years ago
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