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2 years ago

Alexis says she is thinking about a number whose absolute value is 19. What are the possible numbers she could be thinking of?

Mathematics

1 answer:

Grace [21]2 years ago

4 0

Answer:

I do not understand give a genuine question

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Wx+yz=bc solve for x May someone help

Blababa [14]

Wx+yz=bc
-yz. -yz
Wx=bc-yz
Wx/W=bc-yz/W
x=bc-yz/W

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3 years ago

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ira [324]

Answer:

c...

Step-by-step explanation:

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2 years ago

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4.) Which best describes the relationship between < AFB and < AFD?

MAVERICK [17]

Answer:

C. Supplementary angles

Step-by-step explanation:

Given

<AFB = 72

Required

Relationship of <AFB and <AFD

<AFB and <AFD are on a straight line and angle on a straight line is 180

From the presentation of both angles,

<AFB + <AFD = 180

Substitute 72 for <AFB

72 + <AFD = 180

Make <AFB the subject of formula

<AFD = 180 - 72

<AFD = 108

Since both <AFB and <AFD sums to 180, then they are supplementary angles.

Hence, the relationship between both angles is supplementary angles

5 0

3 years ago

Each morning papa notes the birds feeding on his birdfeeder. so far this month he has seen 59 blue jays, 68 black crows, 12 red

Y_Kistochka [10]

The probability would be 59/140 or 42.14% (rounded: 42%).

7 0

3 years ago

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A maritime flag is shown. What is the area of the shaded part of the flag? Explain

Rom4ik [11]

Answer:

$Area = 72in^2$

Step-by-step explanation:

Your question is incomplete without an attachment (See attachment)

Required

Determine the area of the shaded part

From the attachment;

Assume that the shaded portion is closed to the right;

Calculate the Area:

$Area_1 = Length * Width$

$Area_2 = 8in * (6in + 6in)$

$Area_2 = 8in * 12in$

$Area_1 = 96in^2$

Next;

Calculate the Area of the imaginary triangle (on the right)

$Area_2 = \frac{1}{2} * base * height$

$Area_2 = \frac{1}{2} * (6in + 6in) * 4in$

$Area_2 = \frac{1}{2} * 12in * 4in$

$Area_2 = \frac{1}{2} * 48in^2$

$Area_2 = 24in^2$

Lastly, calculate the Area of the Shaded Part

$Area = Area_1 - Area_2$

$Area = 96in^2 - 24in^2$

$Area = 72in^2$

Hence,

The area of the shaded part is 72in²

3 0

2 years ago