Answer:
Chromosomes are a threadlike interrelation of nucleic acids along with protein that is found in the nucleus of most/more of living cells and organisms that carries genetic info in the form of genes.
Chromosomes are what give us our characteristics. In the process of reproducing, the father's DNA will travel through the sperm to the eggs. These eggs, being in the mother, will have her DNA as well. Combining these DNA strands, it can make the hair color of a child, the eye color, ethnicity, and skin color.
Answer:
middle ear- hammer, anvil, stirrup
cochlea- cavern-like bone with tiny hairs and fluid
eardrum- membrane
outer ear- gathers sound
amplify- make greater
This will result to an excitatory postsynaptic potential ((EPSP)
Neurotransmitters are those chemical messages that transmits signals from nerve cells to their target cells.
Neurotransmitters are packed inside vesicles at the presynaptic nerve terminal.
The arrival of an action potential at this terminal leads to opening of Voltage gated channels.
This leads to a change in membrane voltage of the postsynaptic cell following the influx of positively charged ions (sodium ion) into the cell which is called the excitatory postsynaptic potential.
Therefore, excitatory postsynaptic potential ((EPSP) occurs when a neurotransmitter opens a chemically gated ion channel that allowing sodium to enter the postsynaptic cell.
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The limitation of triangulation is it is not accurate to calculate stellar distance.
Explanation:
- In case of triangulation method no specific or uniform method is used . The scientist who use triangulation to measure stellar distance becomes unable to say what type of technique they are using to find the distance. The triangulation method is a combination of various techniques.
- Triangulation can be divided into four parts, they are Data triangulation, theory triangulation, investigator triangulation and lastly methodological triangulation. Triangulation method is used in creating innovative ways.
Answer:
1/4
Explanation:
According to the given information, the dominant plant is back-crossed with a homozygous recessive parent. Therefore, the dominant plant is heterozygous for both genes.
The genotype of the tall plant with smooth seeds would be = TtSs
And the genotype of the dwarf parent with wrinkled seeds = ttss
A cross between TtSs x ttss gives heterozygous tall plants with smooth seeds (TtSs) in 1/4 ratio.
